Concept explainers
A transverse wave on a siring is described by the wave function
where x and y are in meters and t is in seconds. Determine (a) the transverse speed and (b) the transverse acceleration at t = 0.200 s for an element of the string located at x = 1.60 m. What are (c) the wavelength, (d) the period, and (e) the speed of propagation of this wave?
(a)
The transverse speed for an element located at
Answer to Problem 16.15P
The transverse speed for an element located at
Explanation of Solution
Given info: The wave function of the wave is
The standard equation of the transverse wave is,
Here,
The wave function give is,
Compare the equation (1) and equation (2).
The formula to calculate frequency is,
Substitute
The change in position with respect to time gives the transverse speed of the wave.
Here,
Substitute
Differentiate and solve the above expression for
Substitute
Conclusion:
Therefore, the transverse speed for an element located at
(b)
To write: The transverse acceleration of the wave.
Answer to Problem 16.15P
The transverse acceleration of the wave is
Explanation of Solution
Given info: The wave function of the wave is
The change in velocity with respect to time gives the acceleration.
Here,
From equation (1), the speed is,
Substitute
Differentiate and solve the above expression for
Substitute
Solve the above expression.
Conclusion:
Therefore, the transverse acceleration of the wave is
(c)
The wavelength of the wave.
Answer to Problem 16.15P
The wavelength of the wave is
Explanation of Solution
Given info: The wave function of the wave is
The formula to calculate wavelength of the wave is,
Here,
Substitute
Solve the above expression for
Conclusion:
Therefore, the wavelength of the wave is
(d)
The period of the wave.
Answer to Problem 16.15P
The period of the wave is
Explanation of Solution
Given info: The wave function of the wave is
The formula to calculate frequency is,
Here,
Substitute
The formula to calculate time period of the wave is,
Here,
Substitute
Conclusion:
Therefore, the period of the wave is
(E)
The speed of propagation of wave.
Answer to Problem 16.15P
The speed of propagation of wave is
Explanation of Solution
Given info: The wave function of the wave is
The formula to calculate speed of propagation of wave is,
Here,
Substitute
Conclusion:
Therefore, the speed of propagation of wave is
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Chapter 16 Solutions
PHYSICS:F/SCI.+.,V.1-STUD.S.M.+STD.GDE.
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