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EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
9th Edition
ISBN: 8220103611718
Author: SOBHAN
Publisher: CENGAGE L
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Question
Chapter 16, Problem 16.9P
To determine
Find the gross allowable load
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Students have asked these similar questions
7. [Soil Bearing Capacity]
a gross load of 700 kN. Using a factor of safety 3, determine the required value of B. Assume
general shear failure. N. = 63. 53 , Ng = 47.16, N, = 54.36
»). A square footing is shown below. The footing will carry
%3D
Q = 700 kN
y = 17.4 kN/m
0 = 36°
C = 0
1.2 m
B
The water table is at a depth of 2.5 m below the base of a square
footing used to support a column, as shown in figure below.
G.L.
Sand
Y4 = 18 kN/m³
N, = 21
N, = 17
Yat = 20 kN/m³
3 m
The net safe bearing capacity of the footing based on Terzaghi's
bearing capacity equation (in kN/m?) will be.
2.5)
(Take FOS =
2.5 m
1m
b) As shown in the figure below, a rectangular footing (B x L = 2m x 2.2m) is subjected
to a vertical load (400 kN) and moment (100 kN-m). The eccentricity is in the direction
of L. Determine the effective width B'
=
9max =
, and
400 kN
2.2 m
Rock
1
the effective length L'
100 kN-m
Chapter 16 Solutions
EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
Ch. 16 - A continuous footing is shown in Figure 16.17....Ch. 16 - Refer to Problem 16.1. If a square footing with...Ch. 16 - Redo Problem 16.1 with the following: = 115...Ch. 16 - Redo Problem 16.1 with the following: = 16.5...Ch. 16 - Redo Problem 16.1 using the modified general...Ch. 16 - Redo Problem 16.2 using the modified general...Ch. 16 - Redo Problem 16.3 using the modified general...Ch. 16 - Redo Problem 16.4 using the modified general...Ch. 16 - Prob. 16.9PCh. 16 - If the water table in Problem 16.9 drops down to...
Ch. 16 - Prob. 16.11PCh. 16 - A square footing is subjected to an inclined load...Ch. 16 - A square footing (B B) must carry a gross...Ch. 16 - Redo Problem 16.13 with the following data: gross...Ch. 16 - Refer to Problem 16.13. Design the size of the...Ch. 16 - Prob. 16.16PCh. 16 - Prob. 16.17PCh. 16 - Refer to the footing in Problem 16.16. Determine...Ch. 16 - Figure 16.21 shows a continuous foundation with a...Ch. 16 - The following table shows the boring log at a site...
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Similar questions
- 1. A circular footing 3 m in diameter is shown below. [Soil Bearing Capacity] ( Assume the general shear failure and use a factor of safety 2.8. Determine the follow N. = 25.13 , N, = 12.72, N, = 8. 34 a. The gross allowable bearing capacity. b. Net Allowable bearing capacity c. The safe load that the footing can carry. Ground surface Y = 18.5 kN/m³ C = 80 kPa + = 25° 1.1 m D: = 1.8 m Water table Tse = 19.2 kN/m? Diameter = 3 marrow_forwardA square footing (1.5 m × 1.5 m) is located at a depth of 1.0 m. The footing is subjected to an eccentric load of 450 kN, with an eccentricity of 0.2 m along one of the symmetrical axes. Determine the factor of safety against bearing failure. U se Vesic's equation. Take y= 21 kN/m³, c = 100 kN/m², p= 0; N = 5.14; s = 1.14; s = 1; d. 1.27 ; d = 1; i = ig = 1. = q qarrow_forward1. A continuous footing is shown in Figure 16.19. Using Terzaghi's bearing capacity factors, determine the gross allowable load per unit area (4an) that the footing can carry. Assume general shear failure. Given: y = 115 lb/ft, c' = 600 lb/ft', d' = 25°, D, = 3.5 ft, B = 4 ft, and factor of safety = 3. qall Unit weight of soil = y Figure 16.19arrow_forward
- [Soil Bearing Capacity] ( a gross load of 700 kN. Using a factor of safety 3, determine the required value of B. Assume general shear failure. N. = 63. 53,Nq = 47.16, Ny = 54.36 ). A square footing is shown below. The footing will carry Q = 700 kN Y = 17.4 kN/m $ = 36° C = 0 1.2 marrow_forwardA continuous footing is shown in Figure 16.17. Using Terzaghi’s bearing capacity factors, determine the gross allowable load per unit area (all ) that the footing can carry. Assume general shear failure. Given: γ = 19 kN/m3, c′ = 31kN/m2 , , Df = 1.5 m, B = 2 m, and factor of safety = 3.5.arrow_forwardA rectangular footing is constructed on saturated sand. This footing is placed under 1000 KN column load and 500 KN.m moment as shown in the image. Find the eccentricity in both directions and calculate the equivalent footing size. 3.0 M=500 KN.m 0.50 2.5 P1=1000 KN 0.50arrow_forward
- A 1.57 -m. deep 2.5 m. x 3.3c m. footing has to be constructed as shown in Figure 1. The soil properties are: γ=18.7 kN/m3 , γsat=20.9 kN/m3 , angle of friction is 29 degrees, and D1 = 0.55 m. Using FS = 3.3, determine the value of ultimate bearing capacity and the ultimate load capacity (inclined) using β = 17 degrees . (use: γw=9.81 kN/m3)arrow_forwardDetermine the size of square footing to carry net allowable load of 295 KN. FS=3. Use Terzaghi equation assuming general shear failure. 295 kN + = 35° C = 0.0 Ya = 18.15 kN/m3 1 m $ = 25" C = 50 kN/m? Ya = 20 kN/m3arrow_forwardA square footing 2 m x 2 m is located at a depth of 1.2 m below the ground surface. The soilproperties are cohesion, c = 10 kPa, φ = 15 degrees, γ = 16.7 kN/m3, and γsat = 20 kN/m3.Use Terzhagi’s bearing capacity equation: ?? = 1.3??? + ????? + 0.4????, bearingcapacity factors Nc = 12.9, Nq = 4.4, Nγ = 2.5, find qu under the following conditions:arrow_forward
- Q2: A square footing (2x2 m) is constructed on a sandy soil as shown below. Find the maximum allowable load (Q) that the footing can carry. 1.5 m Im Assume general shear failure and the factor of safety is 3. E Y = 16 kN/m 7-18 kN/m 6349arrow_forwardb) As shown in the figure below, a rectangular footing (B x L = 2m x 2.2m) is subjected to a vertical load (400 kN) and moment (100 kN-m). The eccentricity is in the direction of L. Determine the effective width B': , and = 9max = — 400 KN t 2.2 m Y 100 kN-m Rock the effective length =arrow_forward). A circular footing 3 m in diameter is shown below. 6. [Soil Bearing Capacity] (* Assume the general shear failure and use a factor of safety 2.8. Determine the follow N. = 25. 13 , Nq = 12.72, N, = 8.34 a. The gross allowable bearing capacity. b. Net Allowable bearing capacity c. The safe load that the footing can carry. Ground surface Y= 18.5 kN/m? C = 80 kPa = 25° 1.1 m D,- 1.8 m Water table Ye = 19.2 kN/m? Diameter = 3marrow_forward
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