GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY
GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY
4th Edition
ISBN: 9781260908435
Author: SMITH
Publisher: MCG
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Chapter 16, Problem 75P
Interpretation Introduction

(a)

Interpretation:

The products should be identified by the reaction of benzaldehyde with H2,Pd.

Concept Introduction:

Addition of H2gas to a multiple bond is known as hydrogenation. In the presence of palladium metal as the catalyst H2 molecules react with aldehydes and give the respective alcohol of the particular aldehyde.

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  1

Expert Solution
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Answer to Problem 75P

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  2

Explanation of Solution

When an aldehyde reacts with H2 gas in the presence of palladium metal resulting product is an alcohol of the initial aldehyde molecule. Palladium metal act as a catalyst to the reaction that provides a surface to bind both the H2 and carbonyl compound which reduce the activation energy of the reaction.

Hydrogen atoms in the alcohol molecule shown below, which are indicated in red color are the added H during the hydrogenation reaction.

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  3

Interpretation Introduction

(b)

Interpretation:

The products should be identified by the reaction of benzaldehyde with K2Cr2O7.

Concept Introduction:

Addition of an O atom in to a molecule is known as oxidation. The hydrogen atom directly connected to the carbonyl C in an aldehyde will oxidized in the presence of an oxidizing agent such as K2Cr2O7 and give the respective carboxylic acid of the particular aldehyde.

Oxygen atom in the carboxylicacid molecule shown below, which is indicated in red color is the added O during the oxygenation reaction.

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  4

Expert Solution
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Answer to Problem 75P

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  5

Explanation of Solution

When an aldehyde reacts with K2Cr2O7 resulting product is a carboxylic acid of the initial aldehyde molecule. K2Cr2O7 act as an oxidizing agent. Aldehyde's CH bond can be converted in to COH bond.During the reaction red-orange colored K2Cr2O7 solid reduced in to a green color Cr3+ ion.

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  6

Interpretation Introduction

(c)

Interpretation:

The products should be identified by the reaction of benzaldehyde with Ag2O,NH4OH.

Concept Introduction:

Addition of an O atom in to a molecule is known as oxidation. The hydrogen atom directly connected to the carbonyl C in an aldehyde will oxidized in the presence of an oxidizing agent such as ( Ag2O ) in an aqueous medium of ammonium hydroxide( NH4OH ) and give the respective carboxylic acid of the particular aldehyde.

Oxygen atom in the carboxylic acid molecule shown below, which is indicated in red color is the added O during the oxygenation reaction.

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  7

Expert Solution
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Answer to Problem 75P

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  8

Explanation of Solution

When an aldehyde reacts with Ag2O,NH4OH resulting product is a carboxylic acid of the initial aldehyde molecule. Ag2O,NH4OH act as an oxidizing agent. The hydrogen atom directly connected to the carbonyl C in an aldehyde will oxidized in the presence of an oxidizing agent such as ( Ag2O ) in an aqueous medium of ammonium hydroxide( NH4OH ), this Ag2O,NH4OH known as as Tollens reagent.

Aldehyde's CH bond can be converted in to COH bond. During the reaction Ag+ reduced in to Ag metal, which precipitates out of the reaction mixture as a silver mirror.

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  9

  

Interpretation Introduction

(d)

Interpretation:

The products should be identified by the reaction of benzaldehyde with CH3OH(2 equivalents), H2SO4 .

Concept Introduction:

In the presence of alcohol in the acidic medium, aldehydes undergo addition reactions and give acetal in two steps.

Hydrogen atom and CH3 groups in the acetal and hemiacetal molecules shown below, which are indicated in red color are the added molecules during the reaction.

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  10

Expert Solution
Check Mark

Answer to Problem 75P

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  11

Explanation of Solution

In the presence of alcohol in the acidic medium, aldehydes undergo addition reactions and give acetal in two steps. In the first step aldehydes form hemiacetals and during the second step it converts to an acetal molecule of the respective aldehyde molecule.

Addition of one molecule of alcohol in to an aldehyde forms a hemiacetal, one bond of the C=O is broken and two new single bonds are formed. In the presence of CH3OHH2SO4  , acyclic hemiacetals react with another alcohol molecule and produce acetals due to the un stability of the acyclic hemiacetal molecule.

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  12

Interpretation Introduction

(e)

Interpretation:

The products should be identified by the reaction of benzaldehyde with CH3CH2OH(2 equivalents), H2SO4 .

Concept Introduction:

In the presence of alcohol in the acidic medium, aldehydes undergo addition reactions and give acetal in two steps.

Hydrogen atom and CH2CH3 groups in the acetal and hemiacetal molecules shown below, which are indicated in red color are the added molecules during the reaction.

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  13

Expert Solution
Check Mark

Answer to Problem 75P

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  14

Explanation of Solution

In the presence of alcohol in the acidic medium, aldehydes undergo addition reactions and give acetal in two steps. In the first step aldehydes form hemiacetals and during the second step it converts to an acetal molecule of the respective aldehyde molecule.

Addition of one molecule of alcohol in to an aldehyde forms a hemiacetal, one bond of the C=O is broken and two new single bonds are formed. In the presence of CH3CH2OHH2SO4  , acyclic hemiacetals react with another alcohol molecule and produce acetals due to the un stability of the acyclic hemiacetal molecule.

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  15

Interpretation Introduction

(f)

Interpretation:

The products should be identified by the reaction of C6H5CH(OCH2CH3)2 with H2O, H2SO4 .

Concept Introduction:

In the presence of water and acid, acetals undergo hydrolysis reaction and produce aldehydes.

OR' groups in the acetal molecule shown below, which are indicated in red color are the molecules which becomes alcohol molecules during the hydrolysis.

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  16

Expert Solution
Check Mark

Answer to Problem 75P

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  17

Explanation of Solution

Acetals are stable molecules, but their bonds can cleave by a reaction with water and produce aldehydes.

In the acetal molecule, two bonds of the CO are broken and C=O formed, each CH2CH3group becomes a molecule of alcohol.

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY, Chapter 16, Problem 75P , additional homework tip  18

  

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Chapter 16 Solutions

GENERAL, ORGANIC & BIOLOGICAL CHEMISTRY

Ch. 16.5 - What product is formed when each carbonyl compound...Ch. 16.5 - Prob. 16.4PPCh. 16.5 - Prob. 16.9PCh. 16.6 - Prob. 16.5PPCh. 16.6 - Prob. 16.10PCh. 16.6 - Prob. 16.11PCh. 16.7 - Prob. 16.12PCh. 16.8 - Prob. 16.6PPCh. 16.8 - Prob. 16.7PPCh. 16.8 - Prob. 16.13PCh. 16.8 - Prob. 16.8PPCh. 16.8 - Label the three acetalsin solanine, the toxic...Ch. 16.8 - Prob. 16.14PCh. 16.8 - Prob. 16.10PPCh. 16 - Prob. 15PCh. 16 - Prob. 16PCh. 16 - Prob. 17PCh. 16 - Prob. 18PCh. 16 - Prob. 19PCh. 16 - Prob. 20PCh. 16 - Prob. 21PCh. 16 - Prob. 22PCh. 16 - Prob. 23PCh. 16 - Prob. 24PCh. 16 - Give an acceptable name for each ketone. a. b. c....Ch. 16 - Prob. 26PCh. 16 - Prob. 27PCh. 16 - Draw the structure corresponding to each name. a....Ch. 16 - Prob. 29PCh. 16 - Prob. 30PCh. 16 - Prob. 31PCh. 16 - Prob. 32PCh. 16 - Draw out the structure of benzaldehyde, including...Ch. 16 - Prob. 34PCh. 16 - Which compound in each pair has the higher boiling...Ch. 16 - Prob. 36PCh. 16 - Prob. 37PCh. 16 - Prob. 38PCh. 16 - Prob. 39PCh. 16 - Prob. 40PCh. 16 - Prob. 41PCh. 16 - Prob. 42PCh. 16 - Prob. 43PCh. 16 - Prob. 44PCh. 16 - Prob. 45PCh. 16 - Consider the following ball-and-stick model....Ch. 16 - Prob. 47PCh. 16 - Prob. 48PCh. 16 - Prob. 49PCh. 16 - Prob. 50PCh. 16 - Prob. 51PCh. 16 - Prob. 52PCh. 16 - Prob. 53PCh. 16 - Prob. 54PCh. 16 - Prob. 55PCh. 16 - Prob. 56PCh. 16 - Prob. 57PCh. 16 - Prob. 58PCh. 16 - Prob. 59PCh. 16 - Label the functional group(s) in each compound as...Ch. 16 - Prob. 61PCh. 16 - Prob. 62PCh. 16 - What acetal is formed when each aldehyde or ketone...Ch. 16 - What acetal is formed when each aldehyde or ketone...Ch. 16 - Prob. 65PCh. 16 - Prob. 66PCh. 16 - Prob. 67PCh. 16 - Prob. 68PCh. 16 - Prob. 69PCh. 16 - Prob. 70PCh. 16 - Prob. 71PCh. 16 - Prob. 72PCh. 16 - Prob. 73PCh. 16 - Answer each question about phenylacetaldehyde,...Ch. 16 - Prob. 75PCh. 16 - Prob. 76PCh. 16 - Prob. 77PCh. 16 - Prob. 78PCh. 16 - Three constitutional isomers of molecular formula...Ch. 16 - Identify A—C in the following reaction sequenceCh. 16 - Androsterone is a male sex hormone that controls...Ch. 16 - Prob. 82PCh. 16 - Prob. 83PCh. 16 - Prob. 84PCh. 16 - Prob. 85PCh. 16 - Paraldehyde, a hypnotic and sedative once commonly...Ch. 16 - Prob. 87PCh. 16 - Prob. 88PCh. 16 - Prob. 89CPCh. 16 - Prob. 90CP
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