Concept explainers
(a)
An expression for the electric field in the region x>0.
Answer to Problem 90QAP
An expression for the electric field in the region x>0 is,
Explanation of Solution
Given:
Charge,
Charge,
Distance, r
Formula used:
The electric force is given by,
Where,
r=Distance
Calculation:
The electric force is given by,
As charge 1 is placed at origin and charge 2 is placed at a distance a from origin. So, charge 1 is at distance x from reference point and charge 2 is at distance x+a from reference point.
(b)
An expression for the electric field in the region 0
Answer to Problem 90QAP
An expression for the electric field in the region 0
Explanation of Solution
Given:
Charge,
Charge,
Distance, r
Formula used:
The electric force is given by,
Where,
r=DistanceCalculation:
The electric force is given by,
Thus,
(c)
An expression for the electric field in the region x>a.
Answer to Problem 90QAP
An expression for the electric field in the region x>a is,
Explanation of Solution
Given:
Charge,
Charge,
Distance, r
Formula used:
The electric force is given by,
Where,
r=Distance
Calculation:
The electric force is given by,
Thus,
(d)
The point at which the electric field is zero.
Answer to Problem 90QAP
At
Explanation of Solution
Given:
Charge,
Charge,
Distance, r
Formula used:
The electric force is given by,
Where,
r=Distance
Calculation:
The electric force is given by,
Thus,
(e)
To plot:
The graph of Exverses x.
Explanation of Solution
Formula used:
The electric force is given by,
Where,
r=Distance
The electric force is given by,
(f)
An expression for the electric field in the region -8
Answer to Problem 90QAP
An expression for the electric field in the region -8
Explanation of Solution
Given:
Charge,
Charge,
Distance, r
Formula used:
The electric force is given by,
Where,
r=Distance
Calculation:
The electric force is given by,
Thus,
Want to see more full solutions like this?
Chapter 16 Solutions
COLLEGE PHYSICS,VOLUME 1
- A solid conducting sphere of radius 2.00 cm has a charge 8.00 μC. A conducting spherical shell of inner radius 4.00 cm and outer radius 5.00 cm is concentric with the solid sphere and has a total charge −4.00 μC. Find the electric field at (a) r = 1.00 cm, (b) r = 3.00 cm, (c) r = 4.50 cm, and (d) r = 7.00 cm from the center of this charge configuration.arrow_forwardThree identical charges (q = 5.0 C.) lie along a circle of radius 2.0 m at angles of 30, 150, and 270, as shown in Figure P15.33 (page 524). What is the resultant electric field at the center of the circle? Figure P15.33arrow_forwardThree identical charges (q = 5.0 C.) lie along a circle of radius 2.0 m at angles of 30, 150, and 270, as shown in Figure P15.33 (page 524). What is the resultant electric field at the center of the circle? Figure P15.33arrow_forward
- Figure P15.49 shows a closed cylinder with cross-sectional area A = 2.00 m2. The constant electric field E has magnitude 3.50 103 N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines paw through the curved surface. Calculate the electric flux through the cylinder's (a) lop and (b) bottom surface, (c) Determine the amount of charge inside the cylinder. Figure P15.49arrow_forwardFind an expression for the magnitude of the electric field at point A mid-way between the two rings of radius R shown in Figure P24.30. The ring on the left has a uniform charge q1 and the ring on the right has a uniform charge q2. The rings are separated by distance d. Assume the positive x axis points to the right, through the center of the rings. FIGURE P24.30 Problems 30 and 31.arrow_forwardA solid, insulating sphere of radius a has a uniform charge density throughout its volume and a total charge Q. Concentric with this sphere is an uncharged, conducting, hollow sphere whose inner and outer radii are b and c as shown in Figure P19.75. We wish to understand completely the charges and electric fields at all locations. (a) Find the charge contained within a sphere of radius r a. (b) From this value, find the magnitude of the electric field for r a. (c) What charge is contained within a sphere of radius r when a r b? (d) From this value, find the magnitude of the electric field for r when a r b. (e) Now consider r when b r c. What is the magnitude of the electric field for this range of values of r? (f) From this value, what must be the charge on the inner surface of the hollow sphere? (g) From part (f), what must be the charge on the outer surface of the hollow sphere? (h) Consider the three spherical surfaces of radii a, b, and c. Which of these surfaces has the largest magnitude of surface charge density?arrow_forward
- Assume the magnitude of the electric field on each face of the cube of edge L = 1.00 m in Figure P23.32 is uniform and the directions of the fields on each face are as indicated. Find (a) the net electric flux through the cube and (b) the net charge inside the cube. (c) Could the net charge he a single point charge? Figure P23.32arrow_forwardConsider a thin, spherical shell of radius 14.0 cm with a total charge of 32.0 C distributed uniformly on its surface. Find the electric field (a) 10.0 cm and (b) 20.0 cm from the center of the charge distribution.arrow_forwardPanicle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 104 C is at (4.00 m, 0), and panicle C of charge 1.00 104 C is at (0, 3.00 m). (a) What is the x-component of the electric force exerted by A on C? (b) What is the y-component of the force exerted by A on C? (c) Find the magnitude of the force exerted by B on C. (d) Calculate the x-component of the force exerted by B on C. (e) Calculate the y-component of the force exerted by B on C. (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. (g) Repeat part (f) for the y-component. (h) Find the magnitude and direction of the resultant electric force acting on C.arrow_forward
- Consider the charge distribution shown in Active Figure 19.31. (i) What are the charges contributing to the total electric flux through surface S? (a) q1 only (b) q4 only (c) q2 and q3 (d) all four charges (e) none of the charges (ii) What are the charges contributing to the total electric field at a chosen point on the surface S? (a) q1 only (b) q4 only (c) q2 and q3 (d) all four charges (e) none of the charges Active Figure 19.31 The net electric flux through any closed surface depends only on the charge inside that surface. The net flux through surface S is ql/0, the net flux through surface S is (q2 + q3)/0, and the net flux through surface S is zero.arrow_forwardA particle with charge Q = 5.00 C is located at the center of a cube of edge L = 0.100 m. In addition, six other identical charged particles having q = 1.00 C are positioned symmetrically around Q as shown in Figure P19.41. Determine the electric flux through one face of the cube.arrow_forwardA circular ring of charge of radius b has a total charge q uniformly distributed around it. Find the magnitude of the electric field in the center of the ring. (a) 0 (b) keq/b2 (c) keq2/b2 (d) keq2/b (e) None of these answers is correct.arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning