Explanation Given : ∫ ∫ D e x + y d A , the inequalities for domain D- 0 ≤ x ≤ 2 , 0 ≤ y ≤ 2 Calculation : Step 1: The domain D within the square 0 ≤ x , y ≤ 2 is shown in figure Step 2: We denote the unit square 0 ≤ x , y ≤ 1 and the square 0 ≤ x , y ≤ 2 by D 1 and D 2 respectively. Then D 2 is the union of D 1 and D, and these two domains do not overlap except the boundary of D 1 . Therefore, by properties of the double integral, we have ∫ ∫ D 2 e x + y d A = ∫ ∫ D 1 e x + y d A + ∫ ∫ D e x + y d A Step 3: On substituting the appropriate inequalities for domains D 1 and D 2 , we get ∫ ∫ D e x + y d A = ∫ ∫ D 2 e x + y d A −

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ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

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Question

Chapter 16.2, Problem 37E

To determine

The sketch of the domain D where $0 \leq x \leq 2, 0 \leq y \leq 2$ and x or y is greater than 1 and the value of $\int \int_{D} e^{x + y} d A$ .

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Chapter 16.2, Problem 36E

Chapter 16.2, Problem 38E

Chapter 16 Solutions

CALCULUS (CLOTH)

Ch. 16.1 - Prob. 1PQ Ch. 16.1 - Prob. 2PQ Ch. 16.1 - Prob. 3PQ Ch. 16.1 - Prob. 4PQ Ch. 16.1 - Prob. 5PQ Ch. 16.1 - Prob. 6PQ Ch. 16.1 - Prob. 1E Ch. 16.1 - Prob. 2E Ch. 16.1 - Prob. 3E Ch. 16.1 - Prob. 4E

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Prob. 26CRE Ch. 16 - Prob. 27CRE Ch. 16 - Prob. 28CRE Ch. 16 - Prob. 29CRE Ch. 16 - Prob. 30CRE Ch. 16 - Prob. 31CRE Ch. 16 - Prob. 32CRE Ch. 16 - Prob. 33CRE Ch. 16 - Prob. 34CRE Ch. 16 - Prob. 35CRE Ch. 16 - Prob. 36CRE Ch. 16 - Prob. 37CRE Ch. 16 - Prob. 38CRE Ch. 16 - Prob. 39CRE Ch. 16 - Prob. 40CRE Ch. 16 - Prob. 41CRE Ch. 16 - Prob. 42CRE Ch. 16 - Prob. 43CRE Ch. 16 - Prob. 44CRE Ch. 16 - Prob. 45CRE Ch. 16 - Prob. 46CRE Ch. 16 - Prob. 47CRE Ch. 16 - Prob. 48CRE Ch. 16 - Prob. 49CRE Ch. 16 - Prob. 50CRE Ch. 16 - Prob. 51CRE Ch. 16 - Prob. 52CRE Ch. 16 - Prob. 53CRE Ch. 16 - Prob. 54CRE Ch. 16 - Prob. 55CRE Ch. 16 - Prob. 56CRE Ch. 16 - Prob. 57CRE Ch. 16 - Prob. 58CRE Ch. 16 - Prob. 59CRE Ch. 16 - Prob. 60CRE Ch. 16 - Prob. 61CRE

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The sketch of the domain D where 0 ≤ x ≤ 2 , 0 ≤ y ≤ 2 and x or y is greater than 1 and the value of ∫ ∫ D e x + y d A .

Solution Summary: The author calculates the inequalities for the domain D, where x or y is greater than 1 and the value of e

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The sketch of the domain D where $0 \leq x \leq 2, 0 \leq y \leq 2$ and x or y is greater than 1 and the value of $\int \int_{D} e^{x + y} d A$ .

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Chapter 16 Solutions

The sketch of the domain D where 0 ≤ x ≤ 2 , 0 ≤ y ≤ 2 and x or y is greater than 1 and the value of ∫ ∫ D e x + y d A .

Solution Summary: The author calculates the inequalities for the domain D, where x or y is greater than 1 and the value of e

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The sketch of the domain D where 0≤x≤2,0≤y≤2 and x or y is greater than 1 and the value of ∫∫Dex+ydA.

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Chapter 16 Solutions

The sketch of the domain D where $0 \leq x \leq 2, 0 \leq y \leq 2$ and x or y is greater than 1 and the value of $\int \int_{D} e^{x + y} d A$ .