ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<
ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<
9th Edition
ISBN: 9781337034623
Author: McMurry
Publisher: CENGAGE C
Question
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Chapter 16.SE, Problem 77AP
Interpretation Introduction

a)

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 16.SE, Problem 77AP , additional homework tip  1

Interpretation:

The product of the reaction in which actophenone reacts with HNO3 and H2SO4 is to be predicted. The observed regiochemistry is to be explained by drawing the resonance structures of the intermediates.

Concept introduction:

The carbonyl group is an electron withdrawing group. Hence in aromatic electrophilic substitution reactions, the keto group will deactivate the ring and orient the electrophile to the meta position.

To predict:

The product of the reaction in which actophenone reacts with HNO3 and H2SO4.

To explain:

The observed regiochemistry by drawing the resonance structures of the intermediates.

Expert Solution
Check Mark

Answer to Problem 77AP

Actophenone reacts with HNO3 and H2SO4 to produce m-nitroacetophenone.

Explanation of Solution

The electrophile, NO2+, attacks the aromatic ring in the first step to produce a resonance stabilized carbocation (sigma complex). In the second step the carbocation deprotonates to yield the product. For the meta attack the intermediate is more stabilized as shown.

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 16.SE, Problem 77AP , additional homework tip  2

For ortho and para attack one of the resonance forms will be unstable as there will be a positive charge on the carbon to which the carbonyl group is attached.

Conclusion

Actophenone reacts with HNO3 and H2SO4 to produce m-nitroacetophenone.

Interpretation Introduction

b)

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 16.SE, Problem 77AP , additional homework tip  3

Interpretation:

The product of the reaction in which toluene reacts with isopropyl chloride in the presence of AlCl3 is to be predicted. The observed regiochemistry is to be explained by drawing the resonance structures of the intermediates.

Concept introduction:

Alkyl groups are an electron releasing groups. Hence during aromatic electrophilic substitution reactions the alkyl groups will activate the ring and orient the electrophile to the ortho and para positions.

To predict:

The product of the reaction in which toluene reacts with isopropyl chloride in the presence of AlCl3.

To explain:

The observed regiochemistry by drawing the resonance structures of the intermediates.

Expert Solution
Check Mark

Answer to Problem 77AP

When toluene reacts with isopropyl chloride in the presence of AlCl3 the products obtained are o- and p-isopropylbenzenes. The p-isomer will predominate.

Explanation of Solution

The electrophile, (CH3)2CH+, attacks the aromatic ring in the first step to produce a resonance stabilized carbocation (sigma complex). In the second step the carbocation deprotonates to yield the product. For the ortho and para attacks, one of the the resonance structures has a positive charge on a carbon adjacent to the methyl group. This form is stabilized by electron release from the methyl group. Such stabilization is not possible for the meta attack. Hence a mixture of ortho-para products is produced in which the p-isomer predominates.

For ortho attack:

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 16.SE, Problem 77AP , additional homework tip  4

For para attack:

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 16.SE, Problem 77AP , additional homework tip  5

Conclusion

When toluene reacts with isopropyl chloride in the presence of AlCl3 the products obtained are o- and p-isopropylbenzenes. The p-isomer will predominate.

Interpretation Introduction

c)

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 16.SE, Problem 77AP , additional homework tip  6

Interpretation:

The product of the reaction in which benzonitrile reacts with chlorine in the presence of FeCl3 is to be predicted. The observed regiochemistry is to be explained by drawing the resonance structures of the intermediates.

Concept introduction:

The nitrile group is an electron withdrawing group. Hence in aromatic electrophilic substitution reactions the nitrile group will deactivate the ring and orient the electrophile to the meta position.

To predict:

The product of the reaction in which benzonitrile reacts with chlorine in the presence of FeCl3.

To explain:

The observed regiochemistry by drawing the resonance structures of the intermediates.

Expert Solution
Check Mark

Answer to Problem 77AP

When benzonitrile reacts with chlorine in the presence of FeCl3 meta chlorobenzonitrile will be produced.

Explanation of Solution

The electrophile, Cl+, attacks the aromatic ring in the first step to produce a resonance stabilized carbocation (sigma complex). In the second step the carbocation deprotonates to yield the product. For the meta attack the intermediate is more stabilized as shown.

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 16.SE, Problem 77AP , additional homework tip  7

For ortho and para attack one of the resonance forms will be unstable as there will be a positive charge on the carbon to which the nitrile group is attached.

Conclusion

When benzonitrile reacts with chlorine in the presence of FeCl3 meta chlorobenzonitrile will be produced.

Interpretation Introduction

d)

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 16.SE, Problem 77AP , additional homework tip  8

Interpretation:

The product of the reaction in which methoxy benzene reacts with iodine in the presence of CuCl2 is to be predicted. The observed regiochemistry is to be explained by drawing the resonance structures of the intermediates.

Concept introduction:

Methoxy group is an electron releasing group. Hence during aromatic electrophilic substitution reactions the methoxy group will activate the ring and orient the electrophile to the ortho and para positions.

To predict:

The product of the reaction in which benzene reacts with iodine in the presence of CuCl2.

To explain:

The observed regiochemistry by drawing the resonance structures of the intermediates.

Expert Solution
Check Mark

Answer to Problem 77AP

When methoxybenzene reacts with iodine in the presence of CuCl2, the products obtained are o- and p-iodobenzenes.

Explanation of Solution

Iodine itself is unreactive toward aromatic rings. CuCl2 accelerate the iodination reaction by oxidizing iodine to a more powerful by electrophilic species that reacts like I+.

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 16.SE, Problem 77AP , additional homework tip  9

The electrophile, I+, attacks the aromatic ring in the first step to produce a resonance stabilized carbocation (sigma complex). In the second step the carbocation deprotonates to yield the product. For the ortho and para attacks, one of the the resonance structures has a positive charge on a carbon adjacent to the methoxy group. This form is stabilized by electron release from the methoxy group. Such stabilization is not possible for the meta attack. Hence a mixture of ortho-para products is produced.

Ortho attack:

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 16.SE, Problem 77AP , additional homework tip  10

Meta attack:

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<, Chapter 16.SE, Problem 77AP , additional homework tip  11

Conclusion

When methoxybenzene reacts with iodine in the presence of CuCl2, the products obtained are o- and p-iodobenzenes.

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Chapter 16 Solutions

ORGANIC CHEM.(LL)-W/OWL V2 >CUSTOM<

Ch. 16.4 - Prob. 11PCh. 16.4 - Acetanilide is less reactive than aniline toward...Ch. 16.4 - Prob. 13PCh. 16.5 - At what position would you expect electrophilic...Ch. 16.5 - Show the major product(s) from reaction of the...Ch. 16.6 - The herbicide oxyfluorfen can be prepared by...Ch. 16.7 - Treatment of p-bromotoluene with NaOH at 300°C...Ch. 16.8 - Prob. 18PCh. 16.8 - Prob. 19PCh. 16.8 - Prob. 20PCh. 16.9 - Prob. 21PCh. 16.10 - Prob. 22PCh. 16.10 - Prob. 23PCh. 16.SE - Prob. 24VCCh. 16.SE - The following molecular model of a...Ch. 16.SE - Prob. 26VCCh. 16.SE - Prob. 27VCCh. 16.SE - Aromatic iodination can be carried out with a...Ch. 16.SE - Prob. 29MPCh. 16.SE - The carbocation electrophile in a Friede1-Crafts...Ch. 16.SE - Prob. 31MPCh. 16.SE - The nitroso group, —N=O, is one of the few...Ch. 16.SE - Triphenylmethane can be prepared by reaction of...Ch. 16.SE - Using resonance structures of the intermediates,...Ch. 16.SE - Benzene and alkyl -substituted benzenes can be...Ch. 16.SE - Prob. 36MPCh. 16.SE - Hexachlorophene, a substance used in the...Ch. 16.SE - Benzenediazonium carboxylate decomposes when...Ch. 16.SE - 4-Chloropyridine undergoes reaction with...Ch. 16.SE - Propose a mechanism to account for the following...Ch. 16.SE - In the Gatterman-Kochreaction, a formyl group...Ch. 16.SE - Treatment of p-tert-butylphenol with a strong acid...Ch. 16.SE - Benzyl bromide is converted into benzaldehyde by...Ch. 16.SE - Prob. 44MPCh. 16.SE - Prob. 45MPCh. 16.SE - Prob. 46APCh. 16.SE - Prob. 47APCh. 16.SE - Prob. 48APCh. 16.SE - Predict the major monoalkylation products you...Ch. 16.SE - Name and draw the major product(s) of...Ch. 16.SE - Prob. 51APCh. 16.SE - Prob. 52APCh. 16.SE - What product(s) would you expect to obtain from...Ch. 16.SE - Prob. 54APCh. 16.SE - How would you synthesize the following substances...Ch. 16.SE - Prob. 56APCh. 16.SE - Prob. 57APCh. 16.SE - Prob. 58APCh. 16.SE - Prob. 59APCh. 16.SE - Prob. 60APCh. 16.SE - Prob. 61APCh. 16.SE - Prob. 62APCh. 16.SE - Prob. 63APCh. 16.SE - How would you synthesize the following substances...Ch. 16.SE - Prob. 65APCh. 16.SE - Prob. 66APCh. 16.SE - Draw resonance structures of the intermediate...Ch. 16.SE - Prob. 68APCh. 16.SE - p-Bromotoluene reacts with potassium amide to give...Ch. 16.SE - Prob. 70APCh. 16.SE - Prob. 71APCh. 16.SE - Prob. 72APCh. 16.SE - Use your knowledge of directing effects, along...Ch. 16.SE - Identify the reagents represented by the letters...Ch. 16.SE - Phenols (ArOH) are relatively acidic, and the...Ch. 16.SE - Prob. 76APCh. 16.SE - Prob. 77APCh. 16.SE - Melamine, used as a fire retardant and a component...