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Chapter 17, Problem 16P
To determine

The mass of the portion of the string.

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A nylon guitar string is fixed between two lab posts 2.00 m apart. The string has a linear mass density of μ = 7.20 g/m and is placed under a tension of 160.00 N. The string is placed next to a tube, open at both ends, of length L. The string is plucked and the tube resonates at the n = 3 mode. The speed of sound is 343 m/s. What is the length of the tube?
29. A sphere of mass M is supported by a string that passes over a light horizontal rod of length L (Fig. P18.29). Given that the angle is 0 and that f represents the fundamental frequency of standing waves in the portion of the string above the rod, determine the mass of this portion of the string. M Figure P16.30
A phone cord is 4.89 m long. The cord has a mass of 0.212 kg. A transverse wave pulse is produced by plucking one end of the taut cord. That pulse makes four round trips (down and back) along the cord in 0.666 s. What is the tension in the cord? Hint: Four round trips is a total distance of eight lengths of the cord.

Chapter 17 Solutions

Bundle: Physics For Scientists And Engineers With Modern Physics, Loose-leaf Version, 10th + Webassign Printed Access Card For Serway/jewett's Physics For Scientists And Engineers, 10th, Single-term

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