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Engineering Computer Science C++ How To Program (Early Objects Version), Global Edition, With Access Card, 10 Ed

To describe if the given condition creates infinite recursion or not. Given information: There is a program that throws an exception and afterward, the appropriate exception handler starts its execution. Next, the exception handler itself throws an exception. Explanation: The given situation will not create an infinite recursion. This is because the exception handler itself can throw the same exception by using the “throw” keyword without any parameter, which is caught by the outer catch block, if any, else it is handled by the system terminate exception. Example programs: 1. Without throw from catch #include <iostream> using namespace std; int main() { try { throw "Catch Me..."; } catch(const char*c) { cout<<"\nCaught outside "<<c; } return 0; } Output: Explanation There is no throw statement in the catch block, so the compiler throws an exception with “Catch Me…”, which is caught and shown by the catch block. 2. Without outer try.. catch #include <iostream> using namespace std; int main() { try { throw "Catch Me..."; } catch(const char*c) { cout<<"\nCaught outside "<<c; throw; } return 0; } Output: Explanation Terminations by complier on finding throw statement inside catch with no outer catch block to catch the rethrown exception. 3. Using Outer try..catch block #include <iostream> using namespace std; void rethrowfunc() { try { throw "Catch Me....."; } catch (const char*c) { cout<<"\nCaught by function "<<c; throw; } } int main() { try { rethrowfunc(); } catch(const char*c) { cout<<"\nCaught outside "<<c; } cout<<"\n Program continues"; return 0; } Explanation As an exception is first thrown inside the function “rethrowfunc()”, it is caught by its catch block. Inside the catch block when an exception is rethrown, then it is caught by the outer loop and the program is continued afterward. Thus, it does not create infinite recursion as control is transferred to the outer block. Outer catch catches the inner exception thrown is clarified with the string “Catch Me…” displayed which is passed inside the function for throwing an exception. Output

To describe if the given condition creates infinite recursion or not. Given information: There is a program that throws an exception and afterward, the appropriate exception handler starts its execution. Next, the exception handler itself throws an exception. Explanation: The given situation will not create an infinite recursion. This is because the exception handler itself can throw the same exception by using the “throw” keyword without any parameter, which is caught by the outer catch block, if any, else it is handled by the system terminate exception. Example programs: 1. Without throw from catch #include <iostream> using namespace std; int main() { try { throw "Catch Me..."; } catch(const charc) { cout<<"\nCaught outside "<<c; } return 0; } Output: Explanation There is no throw statement in the catch block, so the compiler throws an exception with “Catch Me…”, which is caught and shown by the catch block. 2. Without outer try.. catch #include <iostream> using namespace std; int main() { try { throw "Catch Me..."; } catch(const charc) { cout<<"\nCaught outside "<<c; throw; } return 0; } Output: Explanation Terminations by complier on finding throw statement inside catch with no outer catch block to catch the rethrown exception. 3. Using Outer try..catch block #include <iostream> using namespace std; void rethrowfunc() { try { throw "Catch Me....."; } catch (const charc) { cout<<"\nCaught by function "<<c; throw; } } int main() { try { rethrowfunc(); } catch(const charc) { cout<<"\nCaught outside "<<c; } cout<<"\n Program continues"; return 0; } Explanation As an exception is first thrown inside the function “rethrowfunc()”, it is caught by its catch block. Inside the catch block when an exception is rethrown, then it is caught by the outer loop and the program is continued afterward. Thus, it does not create infinite recursion as control is transferred to the outer block. Outer catch catches the inner exception thrown is clarified with the string “Catch Me…” displayed which is passed inside the function for throwing an exception. Output

Solution Summary: The author explains that the exception handler throws an exception with "Catch Me...", which is caught by the outer catch block.

C++ How To Program (Early Objects Version), Global Edition, With Access Card, 10 Ed

C++ How To Program (Early Objects Version), Global Edition, With Access Card, 10 Ed

10th Edition

ISBN: 9780134448848

Author: Paul Deitel, Harvey Deitel

Publisher: PEARSON

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A file with an extension that has some predefined declarations and definitions is called a header file. Every computer program imports a set of header files to perform common tasks such as getting input, displaying output, and so forth. Every language ha…

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Chapter 17, Problem 17.20E

Chapter 17, Problem 17.22E

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Chapter 17 Solutions

C++ How To Program (Early Objects Version), Global Edition, With Access Card, 10 Ed

Ch. 17 - (Exceptional Conditions) List various exceptional...Ch. 17 - (Catch Parameter) Under what circumstances would...Ch. 17 - (throw Statement) A program contains the statement...Ch. 17 - (Exception Handling vs. Other Schemes) Compare and...Ch. 17 - Prob. 17.19E Ch. 17 - Prob. 17.20E Ch. 17 - Prob. 17.21E Ch. 17 - (Catching Derived-Class Exceptions) Use...Ch. 17 - (Throwing the Result of a Conditional Expression)...Ch. 17 - Prob. 17.24E

Ch. 17 - Prob. 17.25E Ch. 17 - Prob. 17.26E Ch. 17 - Prob. 17.27E Ch. 17 - Prob. 17.28E Ch. 17 - Prob. 17.29E Ch. 17 - Prob. 17.30E Ch. 17 - Prob. 17.31E

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