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Because ΔG° is positive, this reaction does not favor the formation of products. Show how this reaction can be made to proceed by coupling it with the hydrolysis of ATP. Write an equation for the coupled reaction and estimate the equilibrium constant for the coupled process.
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CHEMISTRY-ALEK 360 ACCES 1 SEMESTER ONL
- In each of the following pairs, choose the substance with a lower entropy. (a) One mole of O2(g) with 758 mm Hg pressure, one mole of O2(g) with 493 mm Hg pressure, both at room temperature (b) glucose (s), glucose (aq) (c) Hg(l), Hg(g), both at room temperaturearrow_forwardPick the example with the highest entropy from each of the following sets. Explain your answers. a.Two opposing football teams just before the ball is snapped, two opposing football teams 1 second after the ball is snapped, two opposing football teams when the whistle is blown, ending the play b.A 10 copper/gold alloy, a 2 copper/gold alloy, pure gold c.A purse on which the strap just broke, a purse just hitting the ground, a purse on the ground with contents scattered d.Coins in a piggy bank, coins in piles containing the same type of coins, coins in stacks of the same type of coins e.A dozen loose pearls in a box, a dozen pearls randomly strung on a string, a dozen pearls strung on a string in order of decreasing sizearrow_forwardThe free energy of formation of one mole of compound refers to a particular chemical equation. For each of the following, write that equation. a KBr(s) b CH3Cl(l) c H2S(g) d AsH3(g)arrow_forward
- Consider the following reactions at 25°C: C6H12O6(aq)+6O2(g)6CO2(g)+6H2O G=2870kJ ADP(aq)+HPO42(aq)+2H+(aq)ATP(aq)+H2OG=31kJ Write an equation for a coupled reaction between glucose, C6H12O6, and ADP in which G=390kJ .arrow_forwardIs the following reaction spontaneous as written? Explain. Do whatever calculation is needed to answer the question. CH4(g)+N2(g)HCN(g)+NH3(g)arrow_forwardAccording to a source, lithium peroxide (Li2O2) decomposes to lithium oxide (Li2O) and oxygen gas at about 195C. If the standard enthalpy change for this decomposition is 33.9 kJ/mol, what would you give as an estimate for the standard entropy change for this reaction? Explain.arrow_forward
- The free energy of formation of one mole of compound refers to a particular chemical equation. For each of the following, write that equation. a MgO(s) b COCl2(g) c CF4(g) d PCl5(g)arrow_forwarda Calculate K1, at 25C for sulfurous acid: H2SO3(aq)H+(aq)+HSO3(aq) b Which thermodynamic factor is the most significant in accounting for the fact that sulfurous acid is a weak acid? Why?arrow_forwardImpure nickel, refined by smelting sulfide ores in a blast furnace, can be converted into metal from 99.90% to 99.99% purity by the Mond process. The primary reaction involved in the Mond process is Ni(s)+4CO(g)Ni(CO)4(g) a. Without referring to Appendix 4, predict the sign of S for the above reaction. Explain. b. The spontaneity of the above reaction is temperature-dependent. Predict the sign of Ssurr, for this reaction. Explain c. For Ni(CO)4(g), Hfo=607KJ/mol and S = 417 J/K mol at 298 K. Using these values and data in Appendix 4, calculate H and S for the above reaction. d. Calculate the temperature at which G = 0 (K = 1) for the above reaction, assuming that H and S do not depend on temperature. e. The first step of the Mood process involves equilibrating impure nickel with CO(g) and Ni(CO)4(g) at about 50C. The purpose of this step is to convert as much nickel as possible into the gas phase. Calculate the equilibrium constant for the above reaction at 50.C. f. In the second step of the Mood process, the gaseous Ni(CO)4 is isolated and heated to 227C. The purpose of this step is to deposit as much nickel as possible as pure solid (the reverse of the preceding reaction). Calculate the equilibrium constant for the preceding reaction at 227C. g. Why is temperature increased for the second step of the Mood process? h. The Mond process relies on the volatility of Ni(CO)4 for its success. Only pressures and temperatures at which Ni(CO)4 is a gas are useful. A recently developed variation of the Mood process carries out the first step at higher pressures and a temperature of l52C. Estimate the maximum pressure of Ni(CO)4(g) that can be attained before the gas will liquefy at 152C. The boiling point for Ni(CO)4 is 42C and the enthalpy of vaporization is 29.0 kJ/mol. [Hint: The phase change reaction and the corresponding equilibrium expression are Ni(CO)4(l)Ni(CO)4(g)K=PNi(CO)4 Ni(CO)4(g) will liquefy when the pressure of Ni(CO)4 is greater than the K value.]arrow_forward
- Which contains greater entropy, a quantity of frozen benzene or the same quantity of liquid benzene at the same temperature? Explain in terms of the dispersal of energy in the substance.arrow_forwardCells use the hydrolysis of adenosine triphosphate, abbreviated as ATP, as a source of energy. Symbolically, this reaction can be written as ATP(aq)+H2O(l)ADP(aq)+H2PO4(aq) where ADP represents adenosine diphosphate. For this reaction, G =30.5 kJ/mol. a. Calculate K at 25C. b. If all the free energy from the metabolism of glucose C6H12O6(s)+6O2(g)6CO2(g)+6H2O(l) goes into forming ATP from ADP, how many ATP molecules can be produced for every molecule of glucose?arrow_forwardWhen glucose, C6H12O11, is metabolized to CO2 and H2O in living systems, the first step is the conversion of glucose to glucose-6-phosphate. glucose+H3PO4glucose-6-phosphate+H2OG=13.4kJ This nonspontaneous reaction can be made to proceed by coupling it with the hydrolysis of ATP. ATP+H2OADP+H3PO4G=31.0kJ (a) Write an equation for the coupled reaction and calculate G°. (b) Estimate the number of moles of ATP required to convert glucose to glucose-6-phosphate.arrow_forward
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