Organic Chemistry
Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
Question
Book Icon
Chapter 17, Problem 17.54AP
Interpretation Introduction

(a)

Interpretation:

The reason as to why the trityl radical is an unusually stable radical is to be stated.

Concept introduction:

Resonance is a phenomenon in which polarity is generated in a molecule by the interaction of the conjugated π- bonds or by interaction of the lone pair of electrons and π- bonds. In this phenomenon, the delocalization of the lone pair of electrons occurs. More the resonating structures of a compound, more stable is the compound.

Interpretation Introduction

(b)

Interpretation:

The process of formation of a dimer, hexaphenylethane from the trityl radicals is to be stated.

Concept introduction:

Free radical addition reaction is a reaction in which two stable radicals or a radical and a non radical form a bond by sharing their radicals. The reaction takes place in three steps: chain initiation, chain propagation, and chain termination.

Interpretation Introduction

(c)

Interpretation:

The reason as to why the dimer of two trityl radical, ((4-(diphenylmethylene)cyclohexa-2, 5-dienyl)methanetriyl)tribenzene is formed instead of hexaphenylethane is to be stated.

Concept introduction:

Free radical addition reaction is a reaction in which two stable radicals or a radical and a non radical form a bond by sharing their radicals. The reaction takes place in three steps: chain initiation, chain propagation, and chain termination.

Blurred answer
Students have asked these similar questions
Explain the influence of the electronegative atoms like chlorine on radical stability.
Briefly outline the Woodward-Hoffman description and explain how they can be used to predict if a pericyclic reaction will occur thermally or photochemically.
Account for the CO vibrational frequencies observed in the following metal carbonyl compounds. Compound vco (cm-') Free CO :2143 Ni(CO)4 :1890 cis-Pd(C6F5)2(CO)2: 2186 Explain how and why the degree of metal-alkene back-bonding differs in the compounds K[PtC(CH2=CH2)] and [Pt(CH2=CH2)(PPh3)2]. Compare the reactivity of an alkene bound to a metal centre with that of a free alkene. Give two examples to support your answer.
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Organic Chemistry
    Chemistry
    ISBN:9781305580350
    Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
    Publisher:Cengage Learning
    Text book image
    Organic Chemistry
    Chemistry
    ISBN:9781305080485
    Author:John E. McMurry
    Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305080485
Author:John E. McMurry
Publisher:Cengage Learning