Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 1.7, Problem 28E

To determine

To find : The mean of the positions.

Expert Solution

Answer to Problem 28E

The mean of the positions is −49 meters.

Explanation of Solution

Given information :

The positions of the five free dives from the graph are −46,−40,−48,−51,−60

Calculation :

The mean of the position is the sum of the values of position divided by the number of values. Therefore,

Mean=−46+(−40)+(−48)+(−51)+(−60)5Mean=−2455Mean=−49 m

Thus, the mean of the position is −49 meters.

To determine

To find : The median of the positions.

Expert Solution

Answer to Problem 28E

The median of the positions is −48 meters.

Explanation of Solution

Given information :

The positions of the five free dives from the graph are −46,−40,−48,−51,−60

Calculation :

The median of the position is the middle value of positions when the positions are written in numerical order.

First, arrange the position in order from least to greatest. Therefore,

−60,−51,−48,−46,−40

Since, the number of position is five (i. e. odd), so the median is middle most value (i.e. third value).

Therefore,

Median=−48 m

Thus, the median of the position is −48 meters.

To determine

To compare : Does the mean or the median represent a lower position?

Expert Solution

Answer to Problem 28E

The median represents the lower position.

Explanation of Solution

From part (a) and (b) it can be observed that median is smaller than mean. Therefore, median represents the lower position.

Thus, the median represents the lower position.

Chapter 1.7, Problem 27E

Chapter 1.7, Problem 29E

Chapter 1 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 1.1 - Prob. 1C Ch. 1.1 - Prob. 2C Ch. 1.1 - Prob. 3C Ch. 1.1 - Prob. 4C Ch. 1.1 - Prob. 1E Ch. 1.1 - Prob. 2E Ch. 1.1 - Prob. 3E Ch. 1.1 - Prob. 4E Ch. 1.1 - Prob. 5E Ch. 1.1 - Prob. 6E

Ch. 1.1 - Prob. 7E Ch. 1.1 - Prob. 8E Ch. 1.1 - Prob. 9E Ch. 1.1 - Prob. 10E Ch. 1.1 - Prob. 11E Ch. 1.1 - Prob. 12E Ch. 1.1 - Prob. 13E Ch. 1.1 - Prob. 14E Ch. 1.1 - Prob. 15E Ch. 1.1 - Prob. 16E Ch. 1.1 - Prob. 17E Ch. 1.1 - Prob. 18E Ch. 1.1 - Prob. 19E Ch. 1.1 - Prob. 20E Ch. 1.1 - Prob. 21E Ch. 1.1 - Prob. 22E Ch. 1.1 - Prob. 23E Ch. 1.1 - Prob. 24E Ch. 1.1 - Prob. 25E Ch. 1.1 - Prob. 26E Ch. 1.1 - Prob. 27E Ch. 1.1 - Prob. 28E Ch. 1.1 - Prob. 29E Ch. 1.1 - Prob. 30E Ch. 1.1 - Prob. 31E Ch. 1.1 - Prob. 32E Ch. 1.1 - Prob. 33E Ch. 1.1 - Prob. 34E Ch. 1.1 - Prob. 35E Ch. 1.1 - Prob. 36E Ch. 1.1 - Prob. 37E Ch. 1.1 - Prob. 38E Ch. 1.1 - Prob. 39E Ch. 1.1 - Prob. 40E Ch. 1.1 - Prob. 41E Ch. 1.1 - Prob. 42E Ch. 1.1 - Prob. 43E Ch. 1.1 - Prob. 44E Ch. 1.1 - Prob. 45E Ch. 1.1 - Prob. 46E Ch. 1.1 - Prob. 47E Ch. 1.1 - Prob. 48E Ch. 1.1 - Prob. 49E Ch. 1.1 - Prob. 50E Ch. 1.1 - Prob. 51E Ch. 1.1 - Prob. 52E Ch. 1.1 - Prob. 53E Ch. 1.1 - Prob. 54E Ch. 1.1 - Prob. 55E Ch. 1.1 - Prob. 56E Ch. 1.1 - 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