One Semester Webassign Access Code for Tipler Physics for Scientists and Engineers
9th Edition
ISBN: 9780716778486
Author: Tipler
Publisher: Macmillan Higher Education
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Question
Chapter 17, Problem 59P
(a)
To determine
The rms speed of the argon atoms.
(b)
To determine
Compare the rms speed of the argon atoms with the rms speed of the helium atoms.
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Escape speed from near Earth’s surface is 1.1 x 104 m/s. (a) Find the temperature required for helium gas to have an rms speed equal to that escape speed. (b) Your answer to (a) is much higher than temperatures on Earth. Why then does helium escape from Earth’s atmosphere?
What is the RMS speed of Helium atoms when the temperature of the Helium gas is 312.0 K? (Possibly useful
1.66x10-27 kg, Boltzmann's
constants: the atomic mass of Helium is 4.00 AMU, the Atomic Mass Unit is: 1 AMU
constant is: kg = 1.38×10-23 J/K.)
kB
Submit Answer Tries 0/12
What would be the RMS speed, if the temperature of the Helium gas was doubled?
Submit Answer Tries 0/12
=
Show that the rms speed of molecules in a gas is given by
ЗР
Vrms
where P is the pressure in the gas, and p is the gas density.
Chapter 17 Solutions
One Semester Webassign Access Code for Tipler Physics for Scientists and Engineers
Ch. 17 - Prob. 1PCh. 17 - Prob. 2PCh. 17 - Prob. 3PCh. 17 - Prob. 4PCh. 17 - Prob. 5PCh. 17 - Prob. 6PCh. 17 - Prob. 7PCh. 17 - Prob. 8PCh. 17 - Prob. 9PCh. 17 - Prob. 10P
Ch. 17 - Prob. 11PCh. 17 - Prob. 12PCh. 17 - Prob. 13PCh. 17 - Prob. 14PCh. 17 - Prob. 15PCh. 17 - Prob. 16PCh. 17 - Prob. 17PCh. 17 - Prob. 18PCh. 17 - Prob. 19PCh. 17 - Prob. 20PCh. 17 - Prob. 21PCh. 17 - Prob. 22PCh. 17 - Prob. 23PCh. 17 - Prob. 24PCh. 17 - Prob. 25PCh. 17 - Prob. 26PCh. 17 - Prob. 27PCh. 17 - Prob. 28PCh. 17 - Prob. 29PCh. 17 - Prob. 30PCh. 17 - Prob. 31PCh. 17 - Prob. 32PCh. 17 - Prob. 33PCh. 17 - Prob. 34PCh. 17 - Prob. 35PCh. 17 - Prob. 36PCh. 17 - Prob. 37PCh. 17 - Prob. 38PCh. 17 - Prob. 39PCh. 17 - Prob. 40PCh. 17 - Prob. 41PCh. 17 - Prob. 42PCh. 17 - Prob. 43PCh. 17 - Prob. 44PCh. 17 - Prob. 45PCh. 17 - Prob. 46PCh. 17 - Prob. 47PCh. 17 - Prob. 48PCh. 17 - Prob. 49PCh. 17 - Prob. 50PCh. 17 - Prob. 51PCh. 17 - Prob. 52PCh. 17 - Prob. 53PCh. 17 - Prob. 54PCh. 17 - Prob. 55PCh. 17 - Prob. 56PCh. 17 - Prob. 57PCh. 17 - Prob. 58PCh. 17 - Prob. 59PCh. 17 - Prob. 60PCh. 17 - Prob. 61PCh. 17 - Prob. 62PCh. 17 - Prob. 63PCh. 17 - Prob. 64PCh. 17 - Prob. 65PCh. 17 - Prob. 66PCh. 17 - Prob. 67PCh. 17 - Prob. 68PCh. 17 - Prob. 69PCh. 17 - Prob. 70PCh. 17 - Prob. 71PCh. 17 - Prob. 72PCh. 17 - Prob. 73PCh. 17 - Prob. 74PCh. 17 - Prob. 75PCh. 17 - Prob. 76PCh. 17 - Prob. 77PCh. 17 - Prob. 78PCh. 17 - Prob. 79PCh. 17 - Prob. 80P
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- The van der Waals constants for helium are, L² atm a 0.03412 %D mol? b = 0.0237 mol From these, find the volume in cubic centimeters of a single helium atom. Also estimate the radius of the helium atom.arrow_forwardAn ideal gas is kept in a container of constant volume. The pressure of the gas is also kept constant. (a) Ifthe number of molecules in the gas is doubled, does the rms speedincrease, decrease, or stay the same? Explain. (b) If the initial rmsspeed is 1300 m>s, what is the final rms speed?arrow_forwardIt might seem more natural to give the average speed rather than vrms, but vrms followsmore directly from specific equations. To compute the root of the mean of the squares(rms speed), we square each molecular speed, add, divide by the number of molecules,and take the square root to get vrms.Five gas molecules have speeds of 500, 600, 700, 800, and 900 m/s. Find the gasmolecule’s rms speed and the average speedarrow_forward
- The escape speed from the Earth is 1.12 x 104 m/s so thata gas molecule traveling away from Earth near the outerboundary of the Earth’s atmosphere would, at this speed,be able to escape from the Earth’s gravitational field and belost to the atmosphere. At what temperature is the rmsspeed of (a) oxygen molecules, and (b) helium atomsequal to 1.12 x104 m/s (c) Can you explain why ouratmosphere contains oxygen but not helium?arrow_forwardThe atomic and molecular rms speeds of gases, vrms, are usually quite large, even at low temperatures. What is vrms, in meters per second, for helium atoms at 5.85 K (which is close to the point of liquefaction)?arrow_forwardWhat is the average translational kinetic energy of an ideal-gas molecule at 27 C? (b) What is the total random translational kinetic energy of the molecules in 1 mole of this gas? (c) What is the rms speed of oxygen molecules at this temperature?arrow_forward
- A gas with molecules of radius r and mass per molecule m is at temperature T and pressure p. (a) Write an expression for the mean free time for a molecule moving at the rms speed for this gas. (b) Which single change would have the greatest effect on the mean free time: doubling the radius r, doubling the pressure p, or doubling the temperature T?arrow_forwardHow many molecules are in a typical object, such as gas in a tire or water in a drink? We can use the ideal gas law to give us an idea of how large N typically is.Calculate the number of molecules in a cubic meter of gas at standard temperature and pressure (STP), which is defined to be 0ºC and atmospheric pressure.arrow_forwardProblem 6: The atomic and molecular rms speeds of gases, vrms, are usually quite large, even at low temperatures. What is vrms, in meters per second, for helium atoms at 5.55 K (which is close to the point of liquefaction)?arrow_forward
- A gas is contained in a rigid container of constant volume; the pressure of the gas is also kept constant. If the original rms speed of the gas molecules is 900 m/s, what would be the final rms speed if the number of particles in the gas is doubled?arrow_forwardFor an ideal gas enclosed in a container at temperature T, by using Maxwell’s speed distribution law, derive the expressions for rms speed and most probable speed of its molecules.arrow_forwardA)An ideal gas is confined to a container at a temperature of 330 K.What is the average kinetic energy of an atom of the gas? (Express your answer to two significant figures.) B)2.00 mol of the helium is confined to a 2.00-L container at a pressure of 11.0 atm. The atomic mass of helium is 4.00 u, and the conversion between u and kg is 1 u = 1.661 ××10−27 kg.Calculate vrmsvrms. (Express your answer to three significant figures.) C)A gold (coefficient of linear expansion α=14×10−6K−1α=14×10−6K−1 ) pin is exactly 4.00 cm long when its temperature is 180∘∘C. Find the decrease in long of the pin when it cools to 28.0∘∘C? (Express your answer to two significant figures.)arrow_forward
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