Chapter 17, Problem 6E

Interpretation Introduction

(a)

Interpretation:

The oxidation number for silicon in ${\text{Si}}_2{\text{H}}_6$ is to be stated.

Concept introduction:

Oxidation number is the positive or negative value assigned to an atom in a substance. The number of electrons lost or gained by the elements gives the value of oxidation number. The oxidation number of monoatomic ion is equal to its charge and in free state its value is $0$.

Interpretation Introduction

(b)

Interpretation:

The oxidation number for silicon in ${\text{SiO}}_2$ is to be stated.

Concept introduction:

Oxidation number is the positive or negative value assigned to an atom in a substance. The number of electrons lost or gained by the elements gives the value of oxidation number. The oxidation number of monoatomic ion is equal to its charge and in free state its value is $0$.

Interpretation Introduction

(c)

Interpretation:

The oxidation number for silicon in ${\text{Si}}_3{\text{N}}_4$ is to be stated.

Concept introduction:

Oxidation number is the positive or negative value assigned to an atom in a substance. The number of electrons lost or gained by the elements gives the value of oxidation number. The oxidation number of monoatomic ion is equal to its charge and in free state its value is $0$.

Interpretation Introduction

(d)

Interpretation:

The oxidation number for silicon in ${\text{CaSiO}}_3$ is to be stated.

Concept introduction:

Oxidation number is the positive or negative value assigned to an atom in a substance. The number of electrons lost or gained by the elements gives the value of oxidation number. The oxidation number of monoatomic ion is equal to its charge and in free state its value is $0$.