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Excursions in Modern Mathematics (8E) [Math 11008: Explorations in Modern Mathematics] (Kent State University)
10th Edition
ISBN: 9781269446716
Author: Peter Tannenbaum
Publisher: PEARSON
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Chapter 17, Problem 80E
After polling a random sample of 800 voters during the most recent gubernatorial race, the Tasmania Gazette reports the following:
As the race for governor of Tasmania heads into its final days, our most recent poll shows Mrs. Butterworth ahead of the incumbent Mrs. Cubbison by 6 percentage points 53% to 47%. The results of the poll indicate with near certainty that if the election had been held at the time the poll was taken, Mrs. Butterworth would be the next governor of Tasmania.
a. Estimate the standard error for this poll.
b. Compute a 95% confidence interval for this poll.
c. Compute a 99.7% confidence interval for this poll.
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Chapter 17 Solutions
Excursions in Modern Mathematics (8E) [Math 11008: Explorations in Modern Mathematics] (Kent State University)
Ch. 17 - Consider the normal distribution represented by...Ch. 17 - Consider the normal distribution represented by...Ch. 17 - Consider the normal distribution represented by...Ch. 17 - Consider the normal distribution represented by...Ch. 17 - Consider a normal distribution with mean =81.2lb...Ch. 17 - Consider a normal distribution with mean =2354...Ch. 17 - Consider a normal distribution with first quartile...Ch. 17 - Consider a normal distribution with first quartile...Ch. 17 - Estimate the value of the standard deviation ...Ch. 17 - Estimate the value of the standard deviation ...
Ch. 17 - Explain why a distribution with median M=82, mean...Ch. 17 - Explain why a distribution with median M=453, mean...Ch. 17 - Explain why a distribution with =195, Q1=180 and...Ch. 17 - Explain why a distribution with M==47, Q1=35 and...Ch. 17 - A normal distribution has mean =30kg and standard...Ch. 17 - Prob. 16ECh. 17 - Prob. 17ECh. 17 - Prob. 18ECh. 17 - Prob. 19ECh. 17 - In a normal distribution with mean =83.2 and...Ch. 17 - Prob. 21ECh. 17 - Prob. 22ECh. 17 - Prob. 23ECh. 17 - Prob. 24ECh. 17 - Prob. 25ECh. 17 - In a normal distribution with standard deviation...Ch. 17 - Prob. 27ECh. 17 - Prob. 28ECh. 17 - Consider the normal distribution represented by...Ch. 17 - Consider the normal distribution represented by...Ch. 17 - Consider the normal distribution defined by Fig....Ch. 17 - Consider the normal distribution defined by Fig....Ch. 17 - A normal distribution has mean =71.5in., and the...Ch. 17 - A normal distribution has standard deviation =12.3...Ch. 17 - Prob. 35ECh. 17 - Prob. 36ECh. 17 - Prob. 37ECh. 17 - A normal distribution has mean =500 and standard...Ch. 17 - In a normal distribution, what percent of the data...Ch. 17 - In a normal distribution, what percent of the data...Ch. 17 - Exercises 41 through 44 refer to the following:...Ch. 17 - Exercises 41 through 44 refer to the following:...Ch. 17 - Exercises 41 through 44 refer to the following:...Ch. 17 - Exercises 41 through 44 refer to the following:...Ch. 17 - Exercises 45 through 48 refer to the following: As...Ch. 17 - Exercises 45 through 48 refer to the following: As...Ch. 17 - Exercises 45 through 48 refer to the following: As...Ch. 17 - Exercises 45 through 48 refer to the following: As...Ch. 17 - Exercises 49 through 52 refer to the following:...Ch. 17 - Exercises 49 through 52 refer to the following:...Ch. 17 - Exercises 49 through 52 refer to the following:...Ch. 17 - Exercises 49 through 52 refer to the following:...Ch. 17 - Exercises 53 through 56 refer to the distribution...Ch. 17 - Exercises 53 through 56 refer to the distribution...Ch. 17 - Exercises 53 through 56 refer to the distribution...Ch. 17 - Exercises 53 through 56 refer to the distribution...Ch. 17 - An honest coin is tossed n=3600 times. Let the...Ch. 17 - Prob. 58ECh. 17 - Suppose that a random sample of n=7056 adults is...Ch. 17 - An honest die is rolled. If the roll comes out...Ch. 17 - A dishonest coin with probability of heads p=0.4...Ch. 17 - A dishonest coin with probability of heads p=0.75...Ch. 17 - Prob. 63ECh. 17 - Suppose that 1 out of every 10 plasma televisions...Ch. 17 - Prob. 65ECh. 17 - Prob. 66ECh. 17 - Percentiles. The pth percentile of a sorted data...Ch. 17 - Prob. 68ECh. 17 - Prob. 69ECh. 17 - Percentiles. The pth percentile of a sorted data...Ch. 17 - Prob. 71ECh. 17 - Percentiles. The pth percentile of a sorted data...Ch. 17 - Prob. 73ECh. 17 - Prob. 74ECh. 17 - Prob. 75ECh. 17 - Prob. 76ECh. 17 - A dishonest coin with probability of heads p=0.1...Ch. 17 - Prob. 78ECh. 17 - In American roulette there are 18 red numbers, 18...Ch. 17 - After polling a random sample of 800 voters during...
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