Physics of Everyday Phenomena
9th Edition
ISBN: 9781259894008
Author: W. Thomas Griffith, Juliet Brosing Professor
Publisher: McGraw-Hill Education
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Chapter 17, Problem 9CQ
To determine
Whether the light ray will bent toward the surface normal or away from it.
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Chapter 17 Solutions
Physics of Everyday Phenomena
Ch. 17 - Prob. 1CQCh. 17 - Prob. 2CQCh. 17 - Prob. 3CQCh. 17 - Prob. 4CQCh. 17 - If you want to view your full height in a plane...Ch. 17 - Prob. 6CQCh. 17 - Prob. 7CQCh. 17 - Prob. 8CQCh. 17 - Prob. 9CQCh. 17 - Prob. 10CQ
Ch. 17 - Prob. 11CQCh. 17 - Prob. 12CQCh. 17 - Prob. 13CQCh. 17 - Prob. 14CQCh. 17 - Prob. 15CQCh. 17 - Prob. 16CQCh. 17 - Prob. 17CQCh. 17 - Prob. 18CQCh. 17 - Prob. 19CQCh. 17 - Is there any position in which an object could be...Ch. 17 - Prob. 21CQCh. 17 - Prob. 22CQCh. 17 - Prob. 23CQCh. 17 - Prob. 24CQCh. 17 - Prob. 25CQCh. 17 - Prob. 26CQCh. 17 - Prob. 27CQCh. 17 - Prob. 28CQCh. 17 - Prob. 29CQCh. 17 - For a nearsighted person, is the lens of the...Ch. 17 - Prob. 31CQCh. 17 - Prob. 32CQCh. 17 - Prob. 33CQCh. 17 - Prob. 34CQCh. 17 - Prob. 35CQCh. 17 - Prob. 36CQCh. 17 - A man with a height of 1.7 m stands 2.5 m in front...Ch. 17 - A fish lies 54 cm below the surface of a clear...Ch. 17 - A rock appears to lie just 17 cm below the surface...Ch. 17 - An insect is embedded inside a piece of amber (n =...Ch. 17 - Prob. 5ECh. 17 - Prob. 6ECh. 17 - A positive lens forms a real image of an object...Ch. 17 - Prob. 8ECh. 17 - A magnifying glass with a focal length of +3 cm is...Ch. 17 - A concave mirror has a focal length of 22 cm. An...Ch. 17 - A concave mirror has a focal length of 18 cm. An...Ch. 17 - A convex mirror has a focal length of 15 cm. An...Ch. 17 - Prob. 13ECh. 17 - Prob. 14ECh. 17 - Prob. 15ECh. 17 - Prob. 16ECh. 17 - Prob. 17ECh. 17 - Prob. 1SPCh. 17 - Prob. 2SPCh. 17 - Prob. 3SPCh. 17 - Prob. 4SPCh. 17 - Prob. 5SP
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- Figure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin 1 = n2 sin 2. For paraxial rays, we assume 1 and 2 are small, so we may write n1 tan 1 n2 tan 2. The magnification is defined as M = h/h. Prove that the magnification is given by M = n1q/n2p. Figure P23.28arrow_forwardWhat happens to a light wave when it travels from air into glass? (a) Its speed remains the same. (b) Its speed increases. (c) Its wavelength increases. (d) Its wavelength remains the same. (e) Its frequency remains the same.arrow_forwardUnreasonable results Light traveling from water to a gemstone strikes the surface at an angle of 80.00 and has an angle of refraction of 15.2°. (a) What is the speed of light in the gemstone? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?arrow_forward
- Figure P22.16 shows a light ray traveling in a slab of crown glass surrounded by air. The ray is incident on the right surface at an angle of 55 with the normal and then reflects from points A. B, and C. (a) At which of these points does part of the ray enter the air? (b) If the glass slab is surrounded by carbon disulfide, at which point does part of the ray enter the carbon disulfide?arrow_forwardPierre de Fermat (16011665) showed that whenever light travels from one point to another, its actual path is the path that requires the smallest time interval. This statement is known as Fermats principle. The simplest example is for light propagating in a homogeneous medium. It moves in a straight line because a straight line is the shortest distance between two points. Derive Snells law of refraction from Fermats principle. Proceed as follows. In Figure P34.54, a light ray travels from point P in medium 1 to point Q in medium 2. The two points are, respectively, at perpendicular distances a and b from the interface. The displacement from P to Q has the component d parallel to the interface, and we let x represent the coordinate of the point where the ray enters the second medium. Let t = 0 be the instant the light starts from P. (a) Show that the time at which the light arrives at Q is t=r1v1+r2v2=n1a2+x2c+n2b2+(dx)2c (b) To obtain the value of x for which t has its minimum value, differentiate t with respect to x and set the derivative equal to zero. Show that the result implies n1xa2+x2=n2(dx)b2+(dx)2 (c) Show that this expression in turn gives Snells law. n1sin1=n2sin2 Figure P34.54 Problems 54 and 55.arrow_forwardA person looking into an empty container is able to see the far edge of the containers bottom, as shown in Figure P22.23a. The height of the container is h, and its width is d. When the container is completely filled with a fluid of index of refraction n and viewed from the same angle, the person can see the center of a coin at the middle of the containers bottom, as shown in Figure P22.23b. (a) Show that the ratio h/d is given by hd=n214n2 (b) Assuming the container has a width of 8.00 cm and is filled with water, use the expression above to find the height of the container.arrow_forward
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Laws of Refraction of Light | Don't Memorise; Author: Don't Memorise;https://www.youtube.com/watch?v=4l2thi5_84o;License: Standard YouTube License, CC-BY