Introduction to Algorithms
Introduction to Algorithms
3rd Edition
ISBN: 9780262033848
Author: Thomas H. Cormen, Ronald L. Rivest, Charles E. Leiserson, Clifford Stein
Publisher: MIT Press
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Chapter 17.2, Problem 3E
Program Plan Intro

To show the implementation of a counter as an array of sequence so that INCREMENT and RESET operations take O(n) time.

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Assume (hypothetically) that there is a version of QtSpim that simulates a 4-core processor. Write a MIPS Assembly program that would take advantage of the 4 cores to speed up the execution of mathematical calculations. Specifically, write a program that receives as input two arrays of equal length, and replaces the content of each element in Array 1 with the sum of the corresponding elements in Array 1 and 2.
This problem is adapted from an earlier edition of P&H, and should be submitted.Consider the following code used to implement a new instruction: foo $t3,$t1,$t2:mask : . word 0xFFFFF83Fs t a r t : l a $t0 , masklw $t0 , 0 ( $ t 0 )l a $t3 , s h f t rlw $t3 , 0 ( $ t 3 )and $t3 , $t3 , $ t 0a ndi $t2 , $t2 , 0 x 0 0 1 fs l l $t2 , $t2 , 6o r $t3 , $t3 , $ t 2l a $t5 , s h f t rsw $t3 , 0 ( $ t 5 )s h f t r : s l l $t3 , $t1 , 0Add meaningful comments to the code and write a brief (2 sentence max) description of what foo does. Thisis not the same as saying how it does it - e.g., when asked to describe what a pedestrian is doing, you wouldsay they are walking, not that they are ilfting their left leg, angling it forward, putting it down, . . ..State at least one reason why writing “self-modifying code” such as this is a bad idea (and often times notactually allowed by the operating system)?
For each of the following two code segments, decide whether it is suitable for parallel execution and response according to your justification: add OpenMP pragmas to make the loop parallel or briefly explain why the code segment is not suitable for parallel execution.      (A):      for ( i = 0; i < n; i++ ) {                                                      x [ i ] = 3 * i + 5;                                                                 y [ i ] = log ( x [ i ] );                                                       }                                                                  (B):      x [ 0 ] =  1;                   x [ 1 ] =  2;                 for ( i = 2; i < n; i++ )                     x [ i ] = x [ i – 1 ] * x [ i – 2 ] ;
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