Explanation For funding thesurface integral across the given surface,we have to find the surface integral by parameterizing and then evaluate it. Given: The force function and the points are given below. F = ( 0 , 0 , e y + z ) 0 ≤ x ≤ 1 , 0 ≤ y ≤ 1 , 0 ≤ z ≤ 1 Formula used: ∬ s F . d S = ∬ R F ( G ( x , y ) . N ( x , y ) d x d y Calculation: Now there are six faces three of them are coordinate plane and other three are parallel to coordinate plane such as x = 0 , x = 1 , y = 0 , y = 1 , z = 0 , z = 1 Then normal vectors for each surface are N 1 = ( − 1 , 0 , 0 ) , N 2 = ( 1 , 0 , 0 ) , N 3 = ( 0 , − 1 , 0 ) , N 4 = ( 0 , 1 , 0 ) , N 5 = ( 0 , 0 , − 1 ) , N 6 = ( 0 , 0 , 1 ) respectively Now by using formula ∬ s F . d S = ∬ x = 0 F . N 1 d A + ∬ x = 1 F . N 2 d A + ∬ y = 0 F . N 3 d A + ∬ y = 1 F ...

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ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 17.5, Problem 15E

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To calculate: The surface integral for given vector function and surface.

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Chapter 17.5, Problem 14E

Chapter 17.5, Problem 16E

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Chapter 17 Solutions

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The surface integral for given vector function and surface.

Solution Summary: The author explains how to calculate the surface integral for given vector function and surface.

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To calculate: The surface integral for given vector function and surface.

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Chapter 17 Solutions