MindTap Engineering, 1 term (6 months) Printed Access Card for Das/Sivakugan’s Principles of Foundation Engineering, 9th
9th Edition
ISBN: 9781337705202
Author: Das, Braja M., SIVAKUGAN, Nagaratnam
Publisher: Cengage Learning
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Question
Chapter 18, Problem 18.10P
a.
To determine
Estimate the required depth of sheet pile
b.
To determine
Estimate the force on the tie rods
c.
To determine
Estimate the maximum bending moment in the sheet pile
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P-3 Refer to Figure, for which L, = 2.4 m,
L2 = 4.6 m, y = 15.7 kN/m³, Ysat = 17.3 kN/m³,
and o'=30°, and c= 35 kN/m². Assuming
Sand
c' = 0
C =
Water table
free earth support method:
a. What is the theoretical depth of
embedment, D?
Sand
Ysat
c' = 0
b. What length of sheet piles is needed?
c. Determine the theoretical maximum
moment in the sheet pile.
d. Choose a sheet pile, from next page,
if the the steel pile has a oall = 172 MN/m².
%3D
Clay
D
C
b'= 0
14.10 An anchored sheet-pile bulkhead is shown in Figure P14.10. Let
L₁= 2 m, L₂=6m, /,= 1 m, y = 16 kN/m³, Ysat 18.86 kN/m³, d' = 32°, and
c = 27 kN/m².
a. Determine the theoretical depth of embedment, D.
b. Calculate the anchor force per unit length of the sheet-pile wall.
Use the free earth support method.
只考求D
Water table
Anchor
Sand
Sand
Yo
e'=0
Clay
Figure P14.10
An anchored sheet-pile bulkhead is shown in Figure P14.10. Let L1 = 2 m, L2 = 6 m, l1 = 1 m, γ = 16 kN/m3, γsat = 18.86 kN/m3, Φ' = 32º, and c = 27 kN/m2.a. Determine the theoretical depth of embedment, D.b. Calculate the anchor force per unit length of the sheet-pile wall. Use the free earth support method.
Chapter 18 Solutions
MindTap Engineering, 1 term (6 months) Printed Access Card for Das/Sivakugan’s Principles of Foundation Engineering, 9th
Ch. 18 - Refer to Figure 18.9. A cantilever sheet pile is...Ch. 18 - Prob. 18.2PCh. 18 - Prob. 18.3PCh. 18 - Refer to Figure 18.13. Given L1 = 1.5 m, L2 = 3 m;...Ch. 18 - In Problem 18.4, find the maximum bending moment...Ch. 18 - Prob. 18.6PCh. 18 - Prob. 18.7PCh. 18 - Prob. 18.8PCh. 18 - Refer to Figure 18.23. Given L1=3m, L2=6m,...Ch. 18 - Prob. 18.10P
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