EBK FUNDAMENTALS OF ELECTRIC CIRCUITS
6th Edition
ISBN: 8220102801448
Author: Alexander
Publisher: YUZU
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Chapter 18, Problem 58P
(a)
To determine
Find the carrier frequency of given AM signal
(b)
To determine
Find the lower sideband frequency of AM signal.
(c)
To determine
Find the upper sideband frequency of AM signal.
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Q) Find the spectrum for the following signals in details then find the Nyquist rate for
each of them
(a) m(t) = sin(200nt)/(nt)
(b) m(t) = [sin(200nt)/(nt)]²
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An FM signal has a deviation of 3 kHz and a modulating frequency of 1 kHz. Its total power is 5 W, developed across a 50 Q resistive
load. The carrier frelquency is 160 MHz. Based on the Bessel Table of functions, how many pairs of significant sidebands are there?
A b ho hi ha ho he his he ho ha ho bo
100
0.25 0.98 0.12
0.5
0.94 024
0.03
0.75 O86 0.35 007 001
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0.44
0.11
0.02
1.25 0.65
0.51 0.17 0.04 0.01
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0.56 0.23 0.06 0.01
1.75 037 0.ss 0.29 009 0.02
022 0.58 0.35 0.13 003 0.01
225 0.08
0.55
0.40 0.17 0.05 0.01
24
0.00 0.52 0.43 0.20 006 0.02
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2.75 0.16 0.43
0.47
0.26 0.10 0.03 0.01
-0.26
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35 038
0.40 -0.07 0.36 0.43 028 0.13 0.0s 0.01
45 032 -0.23 0.22 042 0.15 0.20 0.O8 0.03 0.01
0.14 0.46 0.39 0.20 0s 0.03 0.01
-0.18 0.33
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036 0.39 0.26 0.13 0.OS 0.02 0.01
5.5
0.00 -0.34 -0.12 0.26 0.40 0.32 0.19 0.09 0.03 0.01
0.15 0.28 -0.24 0.11 0.36 0.36 0.25 0.13 0.06 0.02
001
6.5
0.26 -0.15 -0.31 -0.03 028 0.37 0.30 0.18…
consider the spectrum magnitude of a signal
shown. From this graph, most nearly, what is
the fundamental frequency of x(t)?
Magnitude Spectra of xt)
25
225
21
1.5
0.5
-1.5
05
0.5
Frequency (Hz)
0.75 Hz
0.25 Hz
The correct answer is not among the alternatives.
0.5 Hz
DC signal, has no fundamental frequency
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Chapter 18 Solutions
EBK FUNDAMENTALS OF ELECTRIC CIRCUITS
Ch. 18.2 - Prob. 1PPCh. 18.2 - Prob. 2PPCh. 18.2 - Prob. 3PPCh. 18.3 - Prob. 5PPCh. 18.3 - Prob. 6PPCh. 18.4 - Prob. 7PPCh. 18.4 - Prob. 8PPCh. 18.5 - (a) Calculate the total energy absorbed by a 1-...Ch. 18.5 - Prob. 10PPCh. 18.8 - If a 2-MHz carrier is modulated by a 4-kHz...
Ch. 18.8 - Prob. 12PPCh. 18 - Prob. 1RQCh. 18 - Prob. 2RQCh. 18 - The inverse Fourier transform of ej2+j is (a) e2t...Ch. 18 - Prob. 4RQCh. 18 - Prob. 5RQCh. 18 - Prob. 6RQCh. 18 - Prob. 7RQCh. 18 - Prob. 8RQCh. 18 - A unit step current is applied through a 1-H...Ch. 18 - Prob. 10RQCh. 18 - Prob. 1PCh. 18 - Prob. 2PCh. 18 - Prob. 3PCh. 18 - Prob. 4PCh. 18 - Prob. 5PCh. 18 - Prob. 6PCh. 18 - Prob. 7PCh. 18 - Prob. 8PCh. 18 - Prob. 9PCh. 18 - Prob. 10PCh. 18 - Prob. 11PCh. 18 - Prob. 12PCh. 18 - Prob. 14PCh. 18 - Prob. 15PCh. 18 - Prob. 16PCh. 18 - Prob. 17PCh. 18 - Given that F=Fft, prove the following results,...Ch. 18 - Prob. 19PCh. 18 - Prob. 21PCh. 18 - Prob. 22PCh. 18 - Prob. 23PCh. 18 - Prob. 24PCh. 18 - Prob. 25PCh. 18 - Prob. 26PCh. 18 - Prob. 27PCh. 18 - Prob. 28PCh. 18 - Prob. 29PCh. 18 - For a linear system with input x(t) and output...Ch. 18 - Prob. 31PCh. 18 - Prob. 32PCh. 18 - Prob. 33PCh. 18 - Prob. 34PCh. 18 - Prob. 35PCh. 18 - Prob. 36PCh. 18 - Prob. 37PCh. 18 - Prob. 38PCh. 18 - Prob. 39PCh. 18 - Prob. 40PCh. 18 - Prob. 41PCh. 18 - Prob. 42PCh. 18 - Prob. 43PCh. 18 - Prob. 44PCh. 18 - Prob. 45PCh. 18 - Prob. 46PCh. 18 - Prob. 47PCh. 18 - Prob. 49PCh. 18 - Prob. 51PCh. 18 - Prob. 52PCh. 18 - Prob. 53PCh. 18 - Prob. 54PCh. 18 - Prob. 55PCh. 18 - Prob. 56PCh. 18 - Prob. 57PCh. 18 - Prob. 58PCh. 18 - Prob. 59PCh. 18 - Prob. 60PCh. 18 - Prob. 61PCh. 18 - Prob. 62PCh. 18 - Prob. 63PCh. 18 - Prob. 64PCh. 18 - Prob. 65PCh. 18 - Prob. 66PCh. 18 - Given a signal g(t) = sinc(200 t), find the...Ch. 18 - Prob. 68CPCh. 18 - Prob. 69CP
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- 1. Determine the fundamental frequency of the given signal and state it's Nyquist rate: a. x(t) = 4.5sin(459nt + 1.2) b. y(t) = cos(55at) – 2cos(19rt)arrow_forwardAn FM signal has a deviation of 3 kHz and a modulating frequency of 1 kHz. Its total power is 5 W, developed across a 50 Q resistive load. The carrier frelquency is 160 MHz. Based on the Bessel Table of functions, how many pairs of significant sidebands are there? ha hi ha ha he hs he ho ha ho ba 100 0.25 0.98 a12 as 0.94 024 a.03 0.75 O6 as a.07 a01 0.77 044 a.I 002 125 0.65 051 a.17 0.04 0.01 LS 0.51 a56 023 006 001 L75 037 O.s8 029 B.09 0.02 022 ass 0.as a13 0.03 0.01 2.25 0.08 0.55 0.40 0.17 0.05 0.01 24 0.00 a52 0.43 0.20 006 0.02 25 0.0s a.50 0.45 0.22 007 0.02 2.75 -0.16 043 047 0.26 0.10 003 a.01 -0.26 034 .49 031 0.13 0.04 0.01 35 038 0.14 0.46 0.39 020 0os 0.03 00I .40 -07 a.36 043 028 0.13 0.0s 0.01 45 032 -0.23 0.22 0.42 0.15 020 0.08 0.03 0.01 0.18 -033 aos 0.36 039 0.26 0.13 0.0s 0.02 a01 0.00 -034 0.12 026 0.40 0.32 0.19 0.09 eas a01 5.5 0.15 0.28 0.24 011 0.36 0.36 0.25 0.13 006 a2 aoI 6.5 026 a15 -0 00s 028 0.7 .30 0.18 0.0 a04 a01 0.30 -001 0.30 -0.17 0.16 035 034 023…arrow_forwardwhat is the value of carrier frequency in the FoMowing equation for fM signal? U(t) = 5Cos(660ot +125in 2500t)arrow_forward
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