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To determine the K sp value of Hg 2 I 2 , a chemist obtained a solid sample of Hg 2 I 2 in which some of the iodine is present as radioactive 131 I. The count rate of the Hg 2 I 2 , sample is 5.0 × 10 11 counts per minute per mole of I. An excess amount of Hg 2 I 2 ( s ) is placed into some water, and the solid is allowed to come to equilibrium with its respective ions. A 150.0-mL sample of the saturated solution is withdrawn and the radioactivity measured at 33 counts per minute. From this information, calculate the K sp value for Hg 2 I 2 . Hg 2 I 2 ( s ) ⇌ HG 2 2 + ( a q ) + 2 I − ( a q ) K sp = [ HG 2 2 + ] [ I − ] 2

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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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Section
BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 18, Problem 85CP
Textbook Problem
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To determine the Ksp value of Hg2I2, a chemist obtained a solid sample of Hg2I2 in which some of the iodine is present as radioactive 131I. The count rate of the Hg2I2, sample is 5.0 × 1011 counts per minute per mole of I. An excess amount of Hg2I2(s) is placed into some water, and the solid is allowed to come to equilibrium with its respective ions. A 150.0-mL sample of the saturated solution is withdrawn and the radioactivity measured at 33 counts per minute. From this information, calculate the Ksp value for Hg2I2.

Hg 2 I 2 ( s ) HG 2 2 + ( a q ) + 2 I ( a q ) K sp = [ HG 2 2 + ] [ I ] 2

Interpretation Introduction

Interpretation: The count rate of Hg2I2 sample is given. An excess amount of Hg2I2 is placed into some water and the solid is allowed to equilibrate with its respective ions. A sample of this solution is withdrawn and the radioactivity is measured. The value of Ksp for Hg2I2 is to be calculated.

Concept introduction:

Solubility product describes the equilibrium relationship between the solid and the ions produced by its dissolution. Higher the Ksp , more soluble is the substance.

To determine: The solubility product (Ksp) for Hg2I2 .

Explanation of Solution

Explanation

One mole of iodide shows 5×1011countspermin .

Therefore, the moles of iodide showing 33 countspermin =335×1011mol=6.6×1011mol

Therefore, the moles of iodide is 6.6×1011mol .

Concentration of iodide in 150ml =6.6×1011mol

Therefore, the concentration of iodide in 1000ml =6.6×1011×1000150mol/L=4.4×1010M

Therefore, the concentration of iodide ions is 4.4×1010M .

The reaction that takes place in the given case is,

Hg2I2(s)Hg22+(aq)+2I(aq)

The solubility is assumed to be s .

The equilibrium concentration for the given reaction is shown in the table given below.

Hg2I2(s)Hg22+(aq)+2I(aq)Initial:s00Equilibrium:0s2s

The equilibrium concentration of iodide is 2s

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Chapter 18 Solutions

Chemistry: An Atoms First Approach
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