Physics
7th Edition
ISBN: 9780321625915
Author: Douglas C. Giancoli
Publisher: PEARSON
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Textbook Question
Chapter 18, Problem 86GP
If a wire of resistance R is stretched uniformly so that its length doubles, by what factor does the power dissipated in the wire change, assuming it remains hooked up to the same voltage source? Assume the wire's volume and density remain constant.
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Look at a circuit
made up of a
resistor, a battery, a
capacitor, and a
switch. Take the time
constant of the circuit
to be 3.12 seconds.
So if the resistor has
a current of 420 mA
and a voltage of 12.0
V when the switch is
closed, calculate the
capacitance of the
capacitor.
In a circuit, all the power delivered by the battery must be dissipated by the elements to the circuit. This is
simply a statement of the conservation of energy. How much energy dissipated depends on the resistance of
the element and the voltage across the resistor, or the current through it. The relevant equations for the
problems are as follows. For a circuit element, the power dissipated (or generated) is P = IV, where Vand I are
the voltage across and current through a circuit element. We know that a resistor obeys OhmA ¢A^A^'s Law
V=IR, which means that for a resistor, the power dissipated is P = I*R = V²/R.
Consider the following two circuits with identical batteries and re-
sistors.
А
В
C
R
R
R RS
R
If the power dissipated by the resistor in circuit A is P, what is the
power dissipated by one resistor in circuit B?
If the power dissipated by the resistor in circuit A is P, what is the
power dissipated by one resistor in circuit C?
A 12.0-V emf automobile battery has a terminal voltage of 16.0 V when being charged by a current of 10.0 A. (a) What is the battery’s internal resistance? (b) What power is dissipated inside the battery? (c) At what rate (in °C/min ) will its temperature increase if its mass is 20.0 kg and it has a specific heat of 0.300 kcal/kg · °C , assuming no heat escapes?
Chapter 18 Solutions
Physics
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