a)
Interpretation: To determine whether
Concept Introduction: Depending on the ability of the ion to react with water the nature of the salt can be determined. If the cation is a strong base and the anion is a strong acid, then the solution or the salt will be neutral. If the cation is a weak base and the anion is a strong acid, then the solution will be acidic. If the cation is a strong base and the anion is a weak acid, then the solution will be basic.
b)
Interpretation: To determine whether
Concept Introduction: Depending on the ability of the ion to react with water, the nature of the salt can be determined. If the cation is a strong base and the anion is a strong acid, then the solution or the salt will be neutral. If the cation is a weak base and the anion is a strong acid, then the solution will be acidic. If the cation is a strong base and the anion is a weak acid, then the solution will be basic.
c)
Interpretation: To determine whether
Concept Introduction: Depending on the ability of the ion to react with water the nature of the salt can be determined. If the cation is a strong base and the anion is a strong acid, then the solution or the salt will be neutral. If the cation is a weak base and the anion is a strong acid, then the solution will be acidic. If the cation is a strong base and the anion is a weak acid, then the solution will be basic.
Want to see the full answer?
Check out a sample textbook solutionChapter 18 Solutions
CHEMISTRY:MOLECULAR...-CONNECT ACCESS
- The active ingredient of bleach such as Clorox is sodium hypochlorite (NaClO). Its conjugate acid, hypochlorous acid (HClO), has a Ka of 3.0 × 10–8. (a) The undiluted bleach contains roughly 1 M NaClO.Calculate the pH of 1 M NaClO solution. (b) Some applications require extremely diluted bleach solution, such as swimming pools. Suppose the solution in (a) is diluted by 10,000-fold. Calculate the pH of the diluted solution, and demonstrate that you can still neglect the autoionization of water in your calculation. (c) Suppose the solution in (a) is diluted by 1 million-fold, briefly explain how your approach willbe different. Write the equation with [H3O+] as the unknown, but you do not need to solve it.arrow_forwardcalculate the pH of the following solution; (a)2.8 × 10–⁴M Ba (OH)2 (b) 5.2 × 10–⁴M HNO3·arrow_forward8. (a) HA(aq) is a weak acid with a dissociation constant, Ka, of 8.8 x 10−12. What is the pH of a 0.022 M solution of A−(aq)? The temperature is 25 ◦C. (b) For the reaction A(g) =A(l), the equilibrium constant is 0.666 at 25.0 ◦C and 0.222 at 75.0 ◦C. Making the approximation that the entropy and enthalpy changes of this reaction do not change with temperature, at what temperature will the equilibrium constant be equal to 0.777?arrow_forward
- Boric acid, H3BO3, is not a Brønsted-Lowry acid but a Lewis acid.(a) Write an equation for its reaction with water.(b) Predict the shape of the anion thus formed.(c) What is the hybridization on the boron consistent with the shape you have predicted?arrow_forward5. The molarity of an aqueous solution of NaOH is 0.0022 M.(a) What is the concentration of H3O+ in this solution?(b) What is the pH of the solution?(c) What is the OH- concentration in the solution?arrow_forwardCalculate the pH of 0.10 M (COOH)2 (aq), oxalic acid. Ka1 = 5.9 × 10–2 ; Ka2 = 6.4 × 10–5.arrow_forward
- Predict whether aqueous solutions of the following substances are acidic, basic, or neutral and write hydrolysis equations for the acidic and basic solutions. (a) CsBr; (b) Al(NO3)3; (c) KCN; (d) CH3NH3Clarrow_forwardThe ionization constant of lactic acid, CH,CH(OH)CO,H, an acid found in the blood after strenuous exercise, is 1.36 x 10-4. What is the concentration of hydronium ion in the solution of 0.102 M lactic acid? CH;CH(OH)CO,H (aq) + H,O (1) → H;O• (aq) + CH;CH(OH)CO, (aq) O 0.00372 M O 0.0165 M O 0.00549 M O 0.227 Marrow_forwardWhat is the conjugate base of boric acid, B(OH)3? (A) OH– (B) B(OH)4– (C) B(O)(OH)22– (D) B(H2O)(OH)2+arrow_forward
- You are given two glasses of water that have different temperatures. The temperature of the first glass is at 298 K, while the second glass has a temperature of 303 K. It has been determined that the Kw value for the second glass of water is 1.47 x 10-¹4. Which of the following statements is true? (a) The pH of the room temperature glass is higher, but both glasses have the same acidity. (b) The room temperature glass of water has a higher pH, and is more basic than the other glass of water. (c) Both glasses of water are neutral, so both will have a pH of 7.00. (d) The room temperature water has a lower pH, so is more acidic. (e) The warmer glass of water has a lower pH, and is more acidic than the other glass of water.arrow_forwardDetermine the pH of each of the following solutions (Ka and Kb values can be found in the appendices of your textbook or online): (a) 0.045 M hypochlorous acid; (b) 0.0068 M phenol; (c) 0.080 M hydroxylamine.arrow_forward6D.17 Calculate the pH of (a) 0.63 M NaCH3 CO₂ (aq); (b) 0.65 M KCN(aq).arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning