(B) Cylindrical Water cans (diameter 6.5cm and length 15cm) are to be cooled from initial temperature of 20˚C by placing theme in a cooler with ambient temperature of 1˚C. Compare the initial cooling rates when the cans are laid horizontally to when the cans are laid vertically. Take v=15.55×10 m³/s, k-0.024 W/mK and Pr-0.7. Nu=0.53Ra for horizontal orientation Nu = 0.59Ra for vertical orientation

(a) How much power is radiated by an iron sphere (emissivity e = 0.60) of radius 24 cm at a temperature of 205°C?  (b) If the sphere is enclosed in a room whose walls are kept at -5°C, what is the net flow rate of energy out of the sphere?

Thus, -195.75 °C, 77.4 K, and -320.35 °F are equivalent temperatures on dif- ferent scales, (b) For a change ATc=[-100°C-(-195.75 °C)]=95.75 c°, we use Eq. 11.3 to find the change in temperature on the Fahrenheit scale as: ATF = ATC = ?I-100 - (-195.75)1 = 172.35 F Thus, a change 95.75 C° = 172.35 F, where the notations C° and F refer to temperature difference, not to be confused with actual temperatures, which are written in terms of symbols °C and °F. (1) The melting point of gold is 10640C and the boiling point is 26600C. (a) Express these temperatures in Kelvins. (b) Compute the difference of these temperatures in Celsius degrees and Kelvin degrees and compare the two numbers. (2) Liquid nitrogen has a boiling point of -195.810C at atmospheric pressure. Express this temperature in (a) degrees Fahrenheit, and (b) kelvins. ANS. (a) -3210F (b) 77.30C (3) A substance is heated from -120F to 1500F. What is its change in temperature on (a) the Celsius scale and (b) kelvin scale? ANS. (a)…