Chapter 1.9, Problem 52MR

To determine

Find which Triangle; the height is not . $4\frac{1}{2}b$ where b is the length of the base.

Answer to Problem 52MR

  $\Delta \text{RST}$

Explanation of Solution

Given:

A chart has shown where the length of height and the base of 4 triangle.

Condition given: $\text{h}=4\frac{1}{2}\text{b}$

Concept Used:

To find the height of each Triangle, we need to multiply each base with $4\frac{1}{2}$

Condition given: $\text{h}=4\frac{1}{2}\text{b}$

Calculation:

Condition given:

Name of the Triangle	Base (cm)	Height (cm)	Yes or No
$\Delta \text{ABC}$	$\text{3}\text{.8}$	$\text{h}\text{=}4.5·\text{3}\text{.8}\text{=}\text{17}\text{.1}$	Yes
$\Delta \text{MQP}$	$\text{5}\text{.4}$	$\text{h}\text{=}4.5·\text{5}\text{.4}\text{=}\text{24}\text{.3}$	Yes
$\Delta \text{RST}$	$\text{6}\text{.3}$	$\text{h}\text{=}4.5·\text{6}\text{.3}\text{=}\text{28}\text{.35}$ Given: $\text{h}\text{=}\text{28}\text{.5}$	No
$\Delta \text{TRW}$	$\text{1}\text{.6}$	$\text{h}\text{=}4.5·\text{1}\text{.6}=7.2$	Yes

Thus, the Triangle $\Delta \text{RST}$ is having different height.