Interpretation:
The
Concept Introduction:
According to the first law of
The equation is as follows.
In voltaic cell, the maximum cell potential is directly related to the free energy difference between the reactants and products in the cell.
The relation between standard cell potential and equilibrium constant is as follows.
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- Calculate E°, G°, and K at 25°C for the reaction 3MnO4(aq)+4H+(aq)+Cl2(g)2Mn2+(aq)+2ClO3(aq)+2H2Oarrow_forwardHydrazine, N2H4, can be used as the reducing agent in a fuel cell. N2H4(aq) + O2(aq) N2(g) + 2 H2O () (a) If rG for the reaction is 598 kJ, calculate the valueof E expected for the reaction. (b) Suppose the equation is written with all coefficients doubled. Determine rG and E for this new reaction.arrow_forwardAn aqueous solution of an unknown salt of gold is electrolyzed by a current of 2.75 amps for 3.39 hours. The electroplating is carried out with an efficiency of 93.0%, resulting in a deposit of 21.221 g of gold. a How many faradays are required to deposit the gold? b What is the charge on the gold ions (based on your calculations)?arrow_forward
- Using values of fH and S, calculate rG for each of the following reactions at 25 C. (a) 2 Pb(s) + O2(g) 2 PbO(s) (b) NH3(g) + HNO3(aq) NH4NO3(aq) Which of these reactions is (are) predicted to be product-favored at equilibrium? Are the reactions enthalpy- or entropy-driven?arrow_forwardAnother type of battery is the alkaline zinc-mercury cell, in which the cell reaction is Zn(s) + HgO(s) Hg() + ZnO(s) E = + 1.35 V (a) What is the standard free energy change for this reaction? (b) The standard free energy change in a voltaic cell is the maximum electrical energy that the cell can produce. If the reaction in a zinc-mercury cell consumes 1.00 g mercury oxide, what is the standard free energy change? (c) For how many hours could a mercury cell produce a 10-mA current if the limiting reactant is 3.50 g mercury oxide?arrow_forwardCalculate the standard cell potential of the cell corresponding to the oxidation of oxalic acid, H2C2O4, by permanganate ion. MnO4. 5H2C2O4(aq)+2MnO4(aq)+6H+(aq)10CO2(g)+2Mn2+(aq)+8H2O(l) See Appendix C for free energies of formation: Gf for H2C2O4(aq) is 698 kJ.arrow_forward
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