Programming with Microsoft Visual Basic 2015 (MindTap Course List)
7th Edition
ISBN: 9781285860268
Author: Diane Zak
Publisher: Cengage Learning
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Expert Solution & Answer
Chapter 1.LC, Problem 1RQ
Program Description Answer
The timer control’s “Tick” event procedure is processed each time an interval has elapsed.
Hence, correct answer is option “B”.
Expert Solution & Answer
Explanation of Solution
Tick event procedure:
The timer is a control, which is used to process any specific task at regular intervals.
- The state of the timer control is of two types. They are running or stopped state.
- Running state:
- If the timer “Enabled” property is set to “True”, then the timer is running.
- If the interval of the Timer has expired, then the timer Tick event occurs each time.
- Therefore, the code in the Tick event procedure is processed each time.
- Stopped state:
- If the timer “Enabled” property is set to “False”, then the timer is stopped.
- The Tick event does not occur in the stop state.
Therefore, the timer control’s Tick event procedure occurs at the end of each interval of the Timer control.
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Students have asked these similar questions
Create a timer program that will take the number of seconds as input, output the remaining time and countdown to 0. You need to output every number, including 0. Sample Input5 Sample Input5 4 3 2 1 0
------------
please help
#include <iostream>
using namespace std;
int main()
{
int seconds;
//cin>>seconds;
//your code goes here
while(seconds <=5)
cout << seconds << endl;
seconds = seconds +1;
return0;
}
Modify the code to add a push button:
Once the code runs it should display the temperature in Fahrenheit only in the serial monitor and when the pus button is pressed the temperature should convert to Celsius . And when it pressed again it should go back to Fahrenheit. 
Right now the code is working but it’s showing the temperature both in cel and Fahrenheit together in the serial monitor . Please modify as asked. Thanks
Please make Flowchart orAlgorithmor a Pseudocode ofthis code
main(){system("color 3");int choice;cout<<"***********************************************************************\n\n\n";cout<<" WELCOME TO EXAM TEST LOGIN \n\n";cout<<"******************* MENU *******************************\n\n";cout<<"1.LOGIN"<<endl;cout<<"2.REGISTER"<<endl;cout<<"3.START EXAM"<<endl;cout<<"4.Exit"<<endl;cout<<"\nEnter your choice :";cin>>choice;cout<<endl;switch(choice){case 1:{ Beep(523,500); // SOUND }login();break;case 2:{ Beep(523,500); // SOUND }registr();break;case 3:{ Beep(523,500); // SOUND }exam();break;case 4:{ Beep(523,500); // SOUND }
cout<<"Thanks for using this program\nThis program is created by Sami, Shahbaz, Hanan, Ahsan, Hamza \n\n";break;default:system("cls");cout<<"You've made a mistake , give it a try again\n"<<endl;main();}}
void exam(){int…
Chapter 1 Solutions
Programming with Microsoft Visual Basic 2015 (MindTap Course List)
Ch. 1.LA - Prob. 1RQCh. 1.LA - Which window is used to set the characteristics...Ch. 1.LA - Prob. 3RQCh. 1.LA - Prob. 4RQCh. 1.LA - Prob. 5RQCh. 1.LA - Prob. 6RQCh. 1.LA - Prob. 7RQCh. 1.LA - Which property determines the initial position of...Ch. 1.LA - Prob. 9RQCh. 1.LA - Prob. 10RQ
Ch. 1.LA - Prob. 11RQCh. 1.LA - Prob. 1ECh. 1.LA - Prob. 2ECh. 1.LA - Prob. 3ECh. 1.LB - Prob. 1RQCh. 1.LB - Prob. 2RQCh. 1.LB - Prob. 3RQCh. 1.LB - Prob. 4RQCh. 1.LB - Prob. 5RQCh. 1.LB - Prob. 1ECh. 1.LB - Prob. 2ECh. 1.LB - Prob. 3ECh. 1.LB - Prob. 4ECh. 1.LC - Prob. 1RQCh. 1.LC - Prob. 2RQCh. 1.LC - Prob. 3RQCh. 1.LC - Prob. 4RQCh. 1.LC - Prob. 5RQCh. 1.LC - Prob. 1ECh. 1.LC - Prob. 2ECh. 1.LC - Prob. 3ECh. 1.LC - Prob. 4ECh. 1.LC - Prob. 5ECh. 1.LC - Prob. 6ECh. 1.LC - Prob. 7ECh. 1.LC - Prob. 8E
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