Concept explainers
(a)
Interpretation:
From the given data, the corresponding elements and the number of each nucleons has to be found.
Concept introduction:
The smallest constituent of matter is atom. Each atom consist of subatomic particles called electrons, protons and neutrons. Protons and neutrons are present in the nucleus and called nucleons. A group of atoms having same number of protons are called as an element.
The atomic
Where
(a)
Answer to Problem 107AE
The given element is found to be phosphorus
Number of protons
Number of neutrons
Explanation of Solution
Given,
Atomic number,
Mass number,
The atomic number of the element is equal to the number of protons.
The mass number is equal to the sum of the number of protons and neutrons.
The element with atomic number 15 was found to be phosphorus
(b)
Interpretation:
From the given data, the corresponding elements and the number of each nucleons has to be found.
Concept introduction:
The smallest constituent of matter is atom. Each atom consist of subatomic particles called electrons, protons and neutrons. Protons and neutrons are present in the nucleus and called nucleons. A group of atoms having same number of protons are called as an element.
The atomic symbol for an element can be represented as
Where
(b)
Answer to Problem 107AE
The given element is found to be potassium
Number of protons
Number of neutrons
Explanation of Solution
Given,
Atomic number,
Mass number,
The atomic number of the element is equal to the number of protons.
The mass number is equal to the sum of the number of protons and neutrons.
The element with atomic number 19 was found to be potassium
(c)
Interpretation:
From the given data, the corresponding elements and the number of each nucleons has to be found.
Concept introduction:
The smallest constituent of matter is atom. Each atom consist of subatomic particles called electrons, protons and neutrons. Protons and neutrons are present in the nucleus and called nucleons. A group of atoms having same number of protons are called as an element.
The atomic symbol for an element can be represented as
Where
(c)
Answer to Problem 107AE
The given element is found to be iodine
Number of protons
Number of neutrons
Explanation of Solution
Given,
Atomic number,
Mass number,
The atomic number of the element is equal to the number of protons.
The mass number is equal to the sum of the number of protons and neutrons.
The element with atomic number 15 was found to be iodine
(d)
Interpretation:
From the given data, the corresponding elements and the number of each nucleons has to be found.
Concept introduction:
The smallest constituent of matter is atom. Each atom consist of subatomic particles called electrons, protons and neutrons. Protons and neutrons are present in the nucleus and called nucleons. A group of atoms having same number of protons are called as an element.
The atomic symbol for an element can be represented as
Where
(d)
Answer to Problem 107AE
The given element is found to be ytterbium
Number of protons
Number of neutrons
Explanation of Solution
Given,
Atomic number,
Mass number,
The atomic number of the element is equal to the number of protons.
The mass number is equal to the sum of the number of protons and neutrons.
The element with atomic number 70 was found to be ytterbium
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Chapter 2 Solutions
Chemistry
- The element rhenium (Re) bas two naturally occurring isotopes, 185Re and 187Re, with an average atomic mass of 186.207 u. Rhenium is 62.60% 187Re, and the atomic mass of 187Re is 186.956 u. Calculate the mass of 185Re.arrow_forwardThe element europium exists in nature as two isotopes: 151Eu has a mass of 150.9196 u and 153Eu has a mass of 152.9209 u. The average atomic mass of europium is 151.96 u. Calculate the relative abundance of the two europium isotopes.arrow_forwardMatch these by placing the correct notation in the appropriate blank. 3467Se3367As3567Br3672Kr a. Contains 33 neutrons b. Contains greatest number of neutrons c. Contains equal number of protons and neutrons d. Contains the same number of neutrons as there are protons in As-67arrow_forward
- An element consists of 1.40% of an isotope with mass 203.973 u, 24.10% of an isotope with mass 205.9745 u, 22.10% of an isotope with mass 206.9759 u, and 52.40% of an isotope with mass 207.Y766 u. Calculate the average atomic mass, and identify the element.arrow_forwardObtain the fractional abundances for the two naturally occurring isotopes of europium. The masses of the isotopes are 151Eu, 150.9196 amu; 153Eu, 152.9209 amu. The atomic weight is 151.9641 amu.arrow_forwardWhen a sample of phosphorus burns in air, the compound P4O10 forms. One experiment showed that 0.744 g of phosphorus formed 1.704 g of P4O10. Use this information to determine the ratio of the atomic weights of phosphorus and oxygen (mass P/mass O). If the atomic weight of oxygen is assumed to be 16.000, calculate the atomic weight of phosphorus.arrow_forward
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