Concept explainers
Short answer exercises: Exercises 1-14 focus on the basic ideas, definitions, and vocabulary of this chapter. Their answers are short (a single sentence or drawing), and you should be able to do them with little or no computation. However, they vary in difficulty, so think carefully before you answer.
13. Sketch the solution curve for the initial-value problem
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Differential Equations
- PA-6 (Applicable to Meteorology or its equivalent case). During their visits at PAGASA- Mactan, the senior high school students were briefed by the agency’s staff. One of the contents in such orientation was on air temperature. In consideration of a period of 12 hours, the staff shared to the students the equivalent model to where the durative condition has to be taken into account as regards air temperature. T = 53 + 5t – 0.3t2 , 0 < t < 12 where t is measured in hours and T in degrees Fahrenheit. With these details, find the average temperature during; (6.1) the first 6-hours (6.2) the entire period (6.3) show the graph of this conditionarrow_forwardAssume that it costs a company approximately C(x) = 529,000 + 160x + 0.001x? dollars to manufacture x units of a device in an hour at one of their manufacturing centers. How many devices should be manufactured each hour to minimize average cost? units What is the resulting average cost of a device? $ How does Read It trage cost compare with the marginal cost at the optimal production level? Find how much they differ.arrow_forwardGiven the description of the phenomena, identify the corresponding mathematical model. A population of fish P(t) lives in an environment with limited resources. As a result, the environment can only support the population if it contains no more than 100, 000 fish (otherwise some fish would starve due to an inadequate supply of food). At any given time, the relative number of additional fish the environment can support is (100, 000 · by 100, 000. Due to the environment, the population grows at a rate proportional to the product of the current P) divided population and the relative number of additional fish the environment can support. dP kP(100,000 – P) a. %D dt 100,000 k(100, 000 – P) b. dP %3D dt 100, 000 C. dP = k(100, 000 – P) dt O d. dP kP %3D dt 100, 000arrow_forward
- A) Solve (D4 + 2D2 + 1)y = x²cosx +3*arrow_forward3x+2y=1 2x-y=10 solve graphicallyarrow_forwardAn automobile costs $20000 when sold brand new and depreciates at a rate of 10% per year. Which of the following equations models the value Vof the car tyears after being sold? O (t) = 20000(1.1)* OV(t) = 20000 – 0.10t O (t) = 20000 + 0.10t V(t) = 20000(0.9) OV(t) = 10 - 20000t Lr Ps hparrow_forward
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage