Answer The solution is s ≤ 14 3 . Given information: The inequality given 2 ( − 4 s + 2 ) ≥ − 5 s − 10 . Calculation: The inequality given, 2 ( − 4 s + 2 ) ≥ − 5 s − 10 . By solving the inequality, 2 ( − 4 s + 2 ) ≥ − 5 s − 10 ⇒ − 8 s + 4 ≥ − 5 s − 10 ⇒ − 8 s + 4 + 5 s ≥ − 10 ⇒ − 3 s ≥ − 10 − 4 ⇒ − 3 s ≥ − 14 ⇒ s ≤ − 14 − 3 ⇒ s ≤ 14 3 When we divide both sides of an inequality by a negative number, sign of the inequality changes. > becomes < and < becomes >. ∴ The solution is s ≤ 14 3 . Explanation Given information: The inequality given 2 ( − 4 s + 2 ) ≥ − 5 s − 10 . Calculation: The inequality given, 2 ( − 4 s + 2 ) ≥ − 5 s − 10 . By solving the inequality, 2 ( − 4 s + 2 ) ≥ − 5 s − 10 ⇒ − 8 s + 4 ≥ − 5 s − 10 ⇒ − 8 s + 4 + 5 s ≥ − 10 ⇒ − 3 s ≥ − 10 − 4 ⇒ − 3 s ≥ − 14 ⇒ s ≤ − 14 − 3 ⇒ s ≤ 14 3 When we divide both sides of an inequality by a negative number, sign of the inequality changes. > becomes < and < becomes >. ∴ The solution is s ≤ 14 3 .

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015

1st Edition

ISBN: 9781680331141

Author: HOUGHTON MIFFLIN HARCOURT

Publisher: Houghton Mifflin Harcourt

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Question

Chapter 2, Problem 18CR

To determine

To calculate: The solution of a given inequality.

Expert Solution & Answer

Answer to Problem 18CR

The solution is s≤143 .

Given information: The inequality given 2(−4s+2)≥−5s−10 .

Calculation:

The inequality given, 2(−4s+2)≥−5s−10 .

By solving the inequality,

2(−4s+2)≥−5s−10⇒−8s+4≥−5s−10⇒−8s+4+5s≥−10⇒−3s≥−10−4⇒−3s≥−14⇒s≤−14−3⇒s≤143

When we divide both sides of an inequality by a negative number, sign of the inequality changes. > becomes < and < becomes >.

∴ The solution is s≤143 .

Explanation of Solution

Given information: The inequality given 2(−4s+2)≥−5s−10 .

Calculation:

The inequality given, 2(−4s+2)≥−5s−10 .

By solving the inequality,

2(−4s+2)≥−5s−10⇒−8s+4≥−5s−10⇒−8s+4+5s≥−10⇒−3s≥−10−4⇒−3s≥−14⇒s≤−14−3⇒s≤143

When we divide both sides of an inequality by a negative number, sign of the inequality changes. > becomes < and < becomes >.

∴ The solution is s≤143 .

Chapter 2, Problem 17CR

Chapter 2, Problem 19CR

Chapter 2 Solutions

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015

Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E

Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.1 - Prob. 37E Ch. 2.1 - Prob. 38E Ch. 2.1 - Prob. 39E Ch. 2.1 - Prob. 40E Ch. 2.1 - Prob. 41E Ch. 2.1 - Prob. 42E Ch. 2.1 - Prob. 43E Ch. 2.1 - Prob. 44E Ch. 2.1 - Prob. 45E Ch. 2.1 - Prob. 46E Ch. 2.1 - Prob. 47E Ch. 2.1 - Prob. 48E Ch. 2.1 - Prob. 49E Ch. 2.1 - Prob. 50E Ch. 2.1 - Prob. 51E Ch. 2.1 - Prob. 52E Ch. 2.1 - Prob. 53E Ch. 2.1 - Prob. 54E Ch. 2.1 - Prob. 55E Ch. 2.1 - Prob. 56E Ch. 2.1 - Prob. 57E Ch. 2.1 - Prob. 58E Ch. 2.1 - Prob. 59E Ch. 2.1 - Prob. 60E Ch. 2.1 - 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