Contemporary Abstract Algebra
Contemporary Abstract Algebra
9th Edition
ISBN: 9781305657960
Author: Joseph Gallian
Publisher: Cengage Learning
bartleby

Videos

Textbook Question
100%
Book Icon
Chapter 2, Problem 1E

Which of the following binary operations are closed?

a. subtraction of positive integers
b. division of nonzero integers
c. function composition of polynomials with real coefficients
d. multiplication of 2 × 2 matrices with integer entries
e. exponentiation of integers

a.

Expert Solution
Check Mark
To determine

Whether the given set is closed or not.

Answer to Problem 1E

The given set of positive integers is not closed under subtraction operation.

Explanation of Solution

Given:

Set of positive integers and operation is subtraction.

Concept Used:

An set G is said to be closed under operation , If abG,a,bG -------(1)

Calculation:

Given setof positive integers is not closedunder the operation subtraction as because there exist some elements a=3,b=5 in G of positive integers,

The result, ab=35=2 is not belongs topositive integers

Hence the given set of positive integers is not closed under subtraction operation.

Conclusion:

The given setof positive integers is not closed under subtraction operation.

b.

Expert Solution
Check Mark
To determine

Whether the given set is closed or not.

Answer to Problem 1E

The set of non zero integers is not closed under division operation.

Explanation of Solution

Given:

Set is non zero integers and operation is division

Concept Used:

An set G is said to be closed under operation , If abG,a,bG -------(1)

Calculation:

Given set non zero of integers is not closed under the operation division as because there exist some elements a=8,b=12 in G of non zero integers,

The result 812=23 is not belongs to in non zero integers.

Hence the given set of non zero integers is not closed under division operation.

Conclusion:

The the given set of non zero integers is not closed under division operation

c.

Expert Solution
Check Mark
To determine

Whether the given set is closed or not.

Answer to Problem 1E

The given set of polynomial functions with real coefficients is closed under composion.

Explanation of Solution

Given:

Set of polynomial functions with real coefficients and operation is composition.

Concept Used:

An set G is said to be closed under operation , If abG,a,bG -------(1)

Calculation:

Given set is closed under the operation composition as because for every elements of a=f(x),b=g(x) in G of polynomial functions is again in G of polynomial functions.

Thus f(x)g(x)G,f(x),g(x)G

Hence the Set of polynomial functions with real coefficients is closed under the operation composition.

Conclusion:

The given the Set of polynomial functions with real coefficients is closed under the operation composition.

d.

Expert Solution
Check Mark
To determine

Whether the given set is closed or not.

Answer to Problem 1E

The given set of matrix of order 2×2 with integer’s entries is closed under multiplication operation.

Explanation of Solution

Given:

Set of matrix of order 2×2 with integer’s entries and operation is multiplication.

Concept Used:

An set G is said to be closed under operation , If ABG,A,BG -------(1)

Calculation:

Given set of matrix of order 2×2 with integer’s entries is closed as because for every elements of A,B in G , the result A×B is again in G.

Thus A×BG,A,BG

Hence the given set of matrix of order 2×2 with integer’s entries is closed underoperation multiplication.

Conclusion:

The given set of matrix of order 2×2 with integer’s entries is closed under multiplication operation.

e.

Expert Solution
Check Mark
To determine

Whether the given set is closed or not.

Answer to Problem 1E

The given set of integers is not closed under exponent operation.

Explanation of Solution

Given:

Set of integers and operation is exponent.

Concept Used:

An set G is said to be closed under operation , If anG,a,nG -------(1)

Calculation:

Given set of integers is not closed under the exponent as because there exist some elements a=2,b=2 in G of integers,

The result, an=22=122=14 is not belongs integers.

Hence the given set of integers is not closed under exponent operation.

Conclusion:

The given set of integers is not closed under exponent operation.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 2 Solutions

Contemporary Abstract Algebra

Ch. 2 - Let a belong to a group and a12=e . Express the...Ch. 2 - In U(9)find the inverse of 2, 7, and 8.Ch. 2 - Translate each of the following multiplicative...Ch. 2 - For group elements a, b, and c, express...Ch. 2 - Suppose that a and b belong to a group and...Ch. 2 - Show that the set {5, 15, 25, 35} is a group under...Ch. 2 - Let G be a group and let H=x1xG . Show that G=H as...Ch. 2 - List the members of K=x2xD4andL=xD4x2=e .Ch. 2 - Prove that the set of all 22 matrices with entries...Ch. 2 - For any integer n2 , show that there are at least...Ch. 2 - An abstract algebra teacher intended to give a...Ch. 2 - Let G be a group with the property that for any x,...Ch. 2 - (Law of Exponents for Abelian Groups) Let a and b...Ch. 2 - (SocksShoes Property) Draw an analogy between the...Ch. 2 - Prove that a group G is Abelian if and only if...Ch. 2 - Prove that in a group, (a1)1=a for all a.Ch. 2 - For any elements a and b from a group and any...Ch. 2 - If a1,a2,...,an belong to a group, what is the...Ch. 2 - The integers 5 and 15 are among a collection of 12...Ch. 2 - Prob. 30ECh. 2 - Prob. 31ECh. 2 - Construct a Cayley table for U(12).Ch. 2 - Suppose the table below is a group table. Fill in...Ch. 2 - Prove that in a group, (ab)2=a2b2 if and only if...Ch. 2 - Let a, b, and c be elements of a group. Solve the...Ch. 2 - Let a and b belong to a group G. Find an x in G...Ch. 2 - Let G be a finite group. Show that the number of...Ch. 2 - Give an example of a group with elements a, b, c,...Ch. 2 - Suppose that G is a group with the property that...Ch. 2 - Find an element X in D4 such that R90VXH=D .Ch. 2 - Suppose F1andF2 are distinct reflections in a...Ch. 2 - Suppose F1andF2 are distinct reflections in a...Ch. 2 - Let R be any fixed rotation and F any fixed...Ch. 2 - Let R be any fixed rotation and F any fixed...Ch. 2 - In the dihedral group Dn , let R=R360/n and let F...Ch. 2 - Prove that the set of all 33 matrices with real...Ch. 2 - Prove that if G is a group with the property that...Ch. 2 - In a finite group, show that the number of...Ch. 2 - List the six elements of GL(2,Z2) . Show that this...Ch. 2 - Prove the assertion made in Example 19 that the...Ch. 2 - Suppose that in the definition of a group G, the...Ch. 2 - Suppose that in the definition of a group G, the...
Knowledge Booster
Background pattern image
Algebra
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Elements Of Modern Algebra
Algebra
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Cengage Learning,
Text book image
Linear Algebra: A Modern Introduction
Algebra
ISBN:9781285463247
Author:David Poole
Publisher:Cengage Learning
Text book image
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:9781133382119
Author:Swokowski
Publisher:Cengage
Text book image
College Algebra
Algebra
ISBN:9781337282291
Author:Ron Larson
Publisher:Cengage Learning
Text book image
Elementary Linear Algebra (MindTap Course List)
Algebra
ISBN:9781305658004
Author:Ron Larson
Publisher:Cengage Learning
Algebraic Complexity with Less Relations; Author: The University of Chicago;https://www.youtube.com/watch?v=ZOKM1JPz650;License: Standard Youtube License
Strassen's Matrix Multiplication - Divide and Conquer - Analysis of Algorithm; Author: Ekeeda;https://www.youtube.com/watch?v=UnpySHwAJsQ;License: Standard YouTube License, CC-BY
Trigonometric Equations with Complex Numbers | Complex Analysis #6; Author: TheMathCoach;https://www.youtube.com/watch?v=zdD8Dab1T2Y;License: Standard YouTube License, CC-BY