Elementary Principles of Chemical Processes, Binder Ready Version
Elementary Principles of Chemical Processes, Binder Ready Version
4th Edition
ISBN: 9781118431221
Author: Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher: WILEY
Question
Chapter 2, Problem 2.1P
Interpretation Introduction

(a)

Interpretation:

: To convert 2 wk to microseconds.

Concept introduction:

The international system of unit (SI units):

Day is represented by the symbol. d
Week is represented by the symbol wk
Hour is represented by the symbol h
Minutes is represented by the symbol min
Seconds is represented by the symbol s
Microsecond is represented by the symbol µs
Meter is represented by the symbol m
Feet is represented by the symbol ft
Kilometer is represented by the symbol km
Kilogram is represented by the symbol kg
Pound is represented by the symbol lb

Expert Solution
Check Mark

Answer to Problem 2.1P

In two weeks there are 1.2×1012μs.

Explanation of Solution

In one week there are seven days and in one day there are twenty-four hours. In one hour there are sixty minutes and in one minute there are sixty seconds. In one second there are 106 microseconds.

Convert week to microseconds as follows:

2wk=(2wk)(7d1wk)(24h1d)(60min1h)(60s1min)(106μs1s)=1.2×1012μs.

Interpretation Introduction

(b)

Interpretation:

To convert 38.1 ft/s to kilometers/h.

Concept introduction:

The international system of unit (SI units):

Day is represented by the symbol d
Week is represented by the symbol wk
Hour is represented by the symbol h
Minutes is represented by the symbol min
Seconds is represented by the symbol s
Microsecond is represented by the symbol µs
Meter is represented by the symbol m
Feet is represented by the symbol ft
Kilometer is represented by the symbol km
Kilogram is represented by the symbol kg
Pound is represented by the symbol lb

Expert Solution
Check Mark

Answer to Problem 2.1P

In 38.1 fts there are 41.8 kmh.

Explanation of Solution

In one day there are twenty-four hours and in one hour there are sixty minutes.

In one pound there are 0.453593 kg and in one feet there are 0.3048 m. Convert meter per day into kilogram to feet per minute into pound as follows:

554m4daykg=(554m4daykg)(1day24 h)(1h60min)(0.453593kg1lbm)(1ft4(0.3048 m)4)=20.2ft4minlbm.

Interpretation Introduction

(c)

Interpretation:

To convert 554 m4/(day.kg) to ft4/(min.lbm ).

Concept introduction:

The international system of unit (SI units):

Day is represented by the symbol d
Week is represented by the symbol wk
Hour is represented by the symbol h
Minutes is represented by the symbol min
Seconds is represented by the symbol s
Microsecond is represented by the symbol µs
Meter is represented by the symbol m
Feet is represented by the symbol ft
Kilometer is represented by the symbol km
Kilogram is represented by the symbol kg
Pound is represented by the symbol lb

Expert Solution
Check Mark

Answer to Problem 2.1P

In 554m4daykg there are 20.2ft4minlbm.

Explanation of Solution

In one day there are twenty-four hours and in one hour there are sixty minutes.

In one pound there are 0.453593 kg and in one feet there are 0.3048 m. Convert meter per day into kilogram to feet per minute into pound as follows:

554m4daykg=(554m4daykg)(1day24 h)(1h60min)(0.453593kg1lbm)(1ft4(0.3048m)4)=20.2ft4minlbm.

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