Chapter 2, Problem 2.27E

Explanation of Solution

Corresponding MIPS instruction:

The corresponding MIPS instruction for the given C code is as follows:

#set i = 0

add $t0, $0, $0

#check i < a

Loop1: slt $t2, $t0, $s0

#if "$t2=0" go to "Exit"

beq $t2, $0, Exit

#set j = 0

add $t1, $0, $0

#check j < b

Loop2: slt $t2, $t1, $s1

#if "$t2=0" go to "Loop3"

beq $t2, $0, Loop3

#add the variable "i" and "j"

add $t2, $t0, $t1

#multiply the "j" with 4

sll $t4, $t1, 4

#storing the "&D[4 * j]" to the "$t3"

add $t3, $t4, $s2

#store the addition of "i" and "j" to the "D[4 * j] "

sw $t2, 0($t3)

#add "1" to the variable "j"

addi $t1, $t1, 1

#jump to the loop2

j Loop2

#add "1" to the variable "i"

Loop3: addi $t0, $t0, 1

#jump to the loop1

j Loop1

Exit:

Explanation:

• Here, “a”, “b”, “i” and “j” are assigned to the registers “$s0”, “$s1”, “$t0” and “$t1” respectively...