COLLEGE PHYSICS-CONNECT ACCESS
COLLEGE PHYSICS-CONNECT ACCESS
5th Edition
ISBN: 9781260486834
Author: GIAMBATTISTA
Publisher: MCG
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Chapter 2, Problem 25P

(a)

To determine

The magnitude and direction of vector.

(a)

Expert Solution
Check Mark

Answer to Problem 25P

The magnitude of the vector is 9.43cm and the direction is 122° from the +x axis.

Explanation of Solution

Write the expression for calculating the magnitude of a vector

  magnitude=x2+y2        (I)

Here, x component, and y component.

Write the expression to calculate the direction,

  θ=tan1(yx)d=θ180°        (II)

Here, θ is the angle, and d is the direction

Conclusion:

Substitute 5.0cm for x, and 8.0cm for y in expression (I)

  magnitude=(5.0cm)2+(8.0cm)2=9.43cm

Substitute 5.0cm for x, and 8.0cm for y in expression (II)   

  θ=tan1(5.0cm8.0cm)=57.99°d=(57.99°)180°=122°from the +x axis.

The magnitude of the vector is 9.43cm and the direction is 122° from the +x axis.

(b)

To determine

The magnitude and direction of vector.

(b)

Expert Solution
Check Mark

Answer to Problem 25P

The magnitude of the vector is |F|=134.16N and the direction is 153.43° from the +x axis.

Explanation of Solution

Write the expression for calculating the magnitude of a vector

  magnitude=x2+y2        (I)

Here, x component, and y component.

Write the expression to calculate the direction,

  θ=tan1(yx)d=θ180°        (II)

Here, θ is the angle, and d is the direction

Conclusion:

Substitute 120N for Fx, and 60N for Fy in expression (I)

  magnitude=(120N)2+(60N)2=134.16N

Substitute 120N for Fx, and 60N for Fy in expression (I)

  θ=tan1(120N60N)=26.56°d=(26.56°)180°=153.43°from the +x axis.

The magnitude of the vector is |F|=134.16N and the direction is 153.43° from the +x axis.

(c)

To determine

The magnitude and direction of vector.

(c)

Expert Solution
Check Mark

Answer to Problem 25P

The magnitude of the vector is |V|=16.28m/s and the direction is 212.71° from the +x axis.

Explanation of Solution

Write the expression for calculating the magnitude of a vector

  magnitude=x2+y2        (I)

Here, x component, and y component.

Write the expression to calculate the direction,

  θ=tan1(yx)d=θ180°        (II)

Here, θ is the angle, and d is the direction

Conclusion:

Substitute 13.7m/s for Vx, and 8.8m/s for Vy in expression (I)

  magnitude=(13.7m/s)2+(8.8m/s)2=16.28m/s

Substitute 13.7m/s for Vx, and 8.8m/s for Vy in expression (I)

  θ=tan1(13.7m/s8.8m/s)=32.71°d=(32.71°)180°=212.71°from the +x axis.

The magnitude of the vector is |V|=16.28m/s and the direction is 212.71° from the +x axis.

(d)

To determine

The magnitude and direction of vector.

(d)

Expert Solution
Check Mark

Answer to Problem 25P

The magnitude of the vector is |a|=6.8m/s2 and the direction is 1.618° from the +x axis.

Explanation of Solution

Write the expression for calculating the magnitude of a vector

  magnitude=x2+y2        (I)

Here, x component, and y component.

Write the expression to calculate the direction,

  θ=tan1(yx)d=θ180°        (II)

Here, θ is the angle, and d is the direction

Conclusion:

Substitute 2.3m/s2 for ax, and 6.5×102m/s2 for ay in expression (I)

  magnitude=(2.3m/s2)2+(6.5×102m/s2)2=2.3m/s2

Substitute 2.3m/s2 for ax, and 6.5×102m/s2 for ay in expression (II)

  θ=tan1(6.5×102m/s22.3m/s2)=1.618°from the +x axis.

The magnitude of the vector is |a|=6.8m/s2 and the direction is 1.618° from the +x axis.

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Chapter 2 Solutions

COLLEGE PHYSICS-CONNECT ACCESS

Ch. 2.4 - Prob. 2.7PPCh. 2.4 - Prob. 2.8PPCh. 2.5 - Prob. 2.9PPCh. 2.5 - Prob. 2.5CPCh. 2.6 - Prob. 2.10PPCh. 2.6 - What would those figs weigh on the surface of the...Ch. 2.6 - Prob. 2.6CPCh. 2.7 - Your laptop is resting on the surface of your...Ch. 2.7 - Suppose the same chest is at rest. You push to the...Ch. 2.7 - Prob. 2.13PPCh. 2.7 - During the seventh-inning stretch of a baseball...Ch. 2.8 - Prob. 2.15PPCh. 2 - Prob. 1CQCh. 2 - Prob. 2CQCh. 2 - Prob. 3CQCh. 2 - Prob. 4CQCh. 2 - An American visitor to Finland is surprised to see...Ch. 2 - Prob. 6CQCh. 2 - Prob. 7CQCh. 2 - Prob. 8CQCh. 2 - Prob. 9CQCh. 2 - Prob. 10CQCh. 2 - Prob. 11CQCh. 2 - Prob. 12CQCh. 2 - Prob. 13CQCh. 2 - Prob. 14CQCh. 2 - Prob. 15CQCh. 2 - Prob. 16CQCh. 2 - Prob. 17CQCh. 2 - Prob. 18CQCh. 2 - Prob. 19CQCh. 2 - Prob. 20CQCh. 2 - Prob. 21CQCh. 2 - Prob. 23CQCh. 2 - Prob. 24CQCh. 2 - Prob. 25CQCh. 2 - Prob. 26CQCh. 2 - Prob. 27CQCh. 2 - Prob. 28CQCh. 2 - Prob. 29CQCh. 2 - Prob. 30CQCh. 2 - Prob. 31CQCh. 2 - Prob. 1MCQCh. 2 - Prob. 2MCQCh. 2 - Prob. 3MCQCh. 2 - Prob. 4MCQCh. 2 - Prob. 5MCQCh. 2 - Prob. 6MCQCh. 2 - Prob. 7MCQCh. 2 - Prob. 8MCQCh. 2 - Prob. 9MCQCh. 2 - Which vector sum is not equal to zero? Ch. 2 - Prob. 11MCQCh. 2 - Prob. 12MCQCh. 2 - Prob. 13MCQCh. 2 - Prob. 14MCQCh. 2 - Prob. 15MCQCh. 2 - Prob. 16MCQCh. 2 - Questions 15–18. For each situation, how does the...Ch. 2 - Prob. 18MCQCh. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Rank the vectors , and in order of increasing...Ch. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10PCh. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - A man is lazily floating on an air mattress in a...Ch. 2 - Prob. 30PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - A hummingbird is hovering motionless beside a...Ch. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - An astronaut stands at a position on the Moon such...Ch. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - A box sits on a horizontal wooden ramp. The...Ch. 2 - Prob. 65PCh. 2 - Prob. 66PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79PCh. 2 - Prob. 80PCh. 2 - Prob. 81PCh. 2 - Prob. 82PCh. 2 - Prob. 83PCh. 2 - Prob. 84PCh. 2 - Prob. 85PCh. 2 - Prob. 86PCh. 2 - Prob. 87PCh. 2 - Prob. 88PCh. 2 - Prob. 89PCh. 2 - Prob. 90PCh. 2 - Prob. 91PCh. 2 - You want to hang a 15 N picture as in the figure...Ch. 2 - Prob. 93PCh. 2 - Prob. 94PCh. 2 - The coefficient of static friction between block A...Ch. 2 - Prob. 96PCh. 2 - Prob. 97PCh. 2 - Prob. 99PCh. 2 - Prob. 100PCh. 2 - Prob. 101PCh. 2 - Prob. 102PCh. 2 - Prob. 103PCh. 2 - Prob. 104PCh. 2 - Prob. 105PCh. 2 - Prob. 106PCh. 2 - Prob. 107PCh. 2 - Prob. 108PCh. 2 - Prob. 109PCh. 2 - Prob. 110PCh. 2 - Prob. 111PCh. 2 - Prob. 112PCh. 2 - Prob. 113PCh. 2 - Prob. 114PCh. 2 - Prob. 115PCh. 2 - Prob. 116PCh. 2 - Prob. 117PCh. 2 - Prob. 118PCh. 2 - Prob. 119PCh. 2 - Prob. 120PCh. 2 - Prob. 121PCh. 2 - Prob. 122PCh. 2 - Prob. 123P
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