Concept explainers
(a)
Interpretation: The product formed by the reaction of Lewis acid
Concept introduction: Lewis acid accepts an electron pair. It acts as an electrophile as it is electron deficient. Lewis base donates an electron pair. It acts as a nucleophile as it is electron loving.
Answer to Problem 2.67P
The product formed by the reaction of
Explanation of Solution
In the given reaction, Lewis base
Figure 1
The product formed by the reaction of
(b)
Interpretation: The product formed by the reaction of Lewis acid
Concept introduction: Lewis acid accepts an electron pair. It acts as an electrophile as it is electron deficient. Lewis base donates an electron pair. It acts as a nucleophile as it is electron loving.
Answer to Problem 2.67P
The product formed by the reaction of
Explanation of Solution
In the given reaction, Lewis base
Figure 2
The product formed by the reaction of
(c)
Interpretation: The product formed by the reaction of Lewis acid
Concept introduction: Lewis acid accepts an electron pair. It acts as an electrophile as it is electron deficient. Lewis base donates an electron pair. It acts as a nucleophile as it is electron loving.
Answer to Problem 2.67P
The product formed by the reaction of
Explanation of Solution
In the given reaction, Lewis base
Figure 3
The product formed by the reaction of
Want to see more full solutions like this?
Chapter 2 Solutions
ORGANIC CHEMISTRY-MOLYMOD PACKAGE
- When the conjugate acid of aniline, C6H5NH3+, reacts with the acetate ion, the following reaction takes place: C6H5NH3+(aq)+CH3COO(aq)C6H5NH2(aq)+CH3COOH(aq) If Kafor C6H5NH3+ is 1.35105 and Kafor CH3COOH is 1.86105 , what is K for the reaction?arrow_forwardMaleic acid and fumaric acid are the cis- and trans- isomers, respectively, of C2H2(COOH)2, a dicarboxylic acid. Draw and label their structures.arrow_forwardThe action of heating one mole of water (containing a trace of acid catalyst) on one mole of compound Y produces one mole of CH,COOH and one mole of CH, CH,NH, The structure of Y is: Select one: O CHCNCCH, CH,CH,NHCH,CH, OH CH CHNHCH,CH, O CHCH,CNHCH; O CH;CH NHÖCH;arrow_forward
- Briefly, but clearly, explain why the –OH hydrogen in acetic acid (CH3CO2H) is more acidic than in ethanol (C2H5OH).arrow_forwardWrite the products of the following acid-base reactions: (a) CH3OH + H2SO4 ² ? (b) CH3OH + NANH2 2 ? (c) CH3NH3+ Cl- + NaOH ?arrow_forwardIdentify the principal organic product in each case NaH CH3C .OH 7arrow_forward
- (HC(CH₂), CO₂) is 9.33 × 106. x Calculate the pH of a 2.8 M solution of trimethylacetic acid. Round your answer to 1 decimal place. The acid dissociation constant K of trimethylacetic acid pH = 0 X 5arrow_forwardNaOH (aq) +KHC8H4O4 =aq)NaKC8H4O4 (aq) + H2O (l) balncearrow_forwardWrite equations to show how the following compounds are oxidized by (1) K2Cr2O7 + H2SO4, (2) Cu2+, or Ag+: (a) 1-propanol (b) 2,3-dimethyl-2-butanolarrow_forward
- O + OHarrow_forwardPropane -42°C 7. The compound shown is a common artificial sweetener. Circle and identify the functional groups in the molecule. Which functional groups can undergo hydrolysis? Draw structures to show the complete hydrolysis (either acidic or basic) of the compound. (Hint: hydrolysis may occur in more than one location.) но. NH CH3 NH2 8. a) Valproic acid is an anti-seizure medication often administered in a sodium salt form. Draw out the reaction showing how the sodium salt of valproic acid is formed. Why is the salt form used? CH, – CH, - CH als folos CH – c CH, - CH, – CH Vinim OH Valproic Acid b) Phenylpropanolamine (PPA) is a decongestant and appetite suppressant medication that is no longer available in the US and Canada because of its association with increased stroke risk. It is administered in a hydrochloride salt form. Draw out the reaction showing how the hydrochloride salt of phenylpropanolamine is formed. Why is the salt form used? нн -NH2 ÓH CH3 phenylpropanolaminearrow_forwarda) If the pH value of an aqueous solution of trimethylamine [(CH3)3N] is 10.75, what should be the molarity of this solution? (CH3)3N + H2O ↔ (CH3)3NH+ + OH-, Kb = 6,3 × 10-5 b) What will be the pH of the solution prepared by dissolving 8.35 g of aniline hydrochloride (C6H5NH3+Cl-) in 750 mL of 0.215 M aniline (C6H5NH2)? Is this solution an effective buffer? Explain (Kb = 7,4 × 10-10 for aniline, C: 12.0 g / mol, H: 1.0 g / mol, N: 14.0 g / mol, Cl: 35.4 g / mol) .arrow_forward
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning