21ST CENTURY ASTR.:SOLAR..(LL)-PACKAGE
6th Edition
ISBN: 9780393448498
Author: Kay
Publisher: NORTON
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Chapter 2, Problem 44QP
To determine
Find the how much large would the Earth appear for the person in the Moon.
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The moon is about 3.8 × 10^5 km from Earth. How many centimeters is this? One km = 100,000 cm. Write your answer in scientific notation
From Earth, the angular size of the Moon is 0.5 degree. The distance between the Earth and the Moon is 384,400 km. Use the small-angle formula to find the size of the Moon. Compare the number to the distance of the Moon given previously. It is consistent?
d. Diameter of the Sun
I h
A
d.
Standing on the beach at sunset, you extend the tip of your finger at your full arm length from
your face, covering the Sun. Upon moving your finger around, you find that only about half of its
width is needed to completely cover the Sun's diameter. You measure your finger width to be 0.5
inches. You know your arm length to be 28.0 inches. You have be told that the Sun is
approximately 93 million miles away. Use this information to determine the approximate
diameter of the Sun, filling in the table below with the proper quantities measure in meters.
1 = ½ finger
g = eye level
height
d = object
h = Diameter
f= object
height from
level to top of eye level
X = Arm
A =
angle
width
length
distance
from eye
of the Sun
object
Chapter 2 Solutions
21ST CENTURY ASTR.:SOLAR..(LL)-PACKAGE
Ch. 2.1 - Prob. 2.1ACYUCh. 2.1 - Prob. 2.1BCYUCh. 2.2 - Prob. 2.2CYUCh. 2.3 - Prob. 2.3CYUCh. 2.4 - Prob. 2.4CYUCh. 2.5 - Prob. 2.5CYUCh. 2 - Prob. 1QPCh. 2 - Prob. 2QPCh. 2 - Prob. 3QPCh. 2 - Prob. 4QP
Ch. 2 - Prob. 5QPCh. 2 - Prob. 6QPCh. 2 - Prob. 7QPCh. 2 - Prob. 8QPCh. 2 - Prob. 9QPCh. 2 - Prob. 10QPCh. 2 - Prob. 11QPCh. 2 - Prob. 12QPCh. 2 - Prob. 13QPCh. 2 - Prob. 14QPCh. 2 - Prob. 15QPCh. 2 - Prob. 16QPCh. 2 - Prob. 17QPCh. 2 - Prob. 18QPCh. 2 - Prob. 19QPCh. 2 - Prob. 20QPCh. 2 - Prob. 21QPCh. 2 - Prob. 22QPCh. 2 - Prob. 23QPCh. 2 - Prob. 24QPCh. 2 - Prob. 25QPCh. 2 - Prob. 26QPCh. 2 - Prob. 27QPCh. 2 - Prob. 28QPCh. 2 - Prob. 29QPCh. 2 - Prob. 30QPCh. 2 - Prob. 31QPCh. 2 - Prob. 33QPCh. 2 - Prob. 34QPCh. 2 - Prob. 35QPCh. 2 - Prob. 36QPCh. 2 - Prob. 37QPCh. 2 - Prob. 38QPCh. 2 - Prob. 39QPCh. 2 - Prob. 40QPCh. 2 - Prob. 41QPCh. 2 - Prob. 42QPCh. 2 - Prob. 43QPCh. 2 - Prob. 44QPCh. 2 - Prob. 45QP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The day on Mars is 1.026 Earth-days long. The martian year lasts 686.98 Earth-days. The two moons of Mars take 0.32 Earth-day (for Phobos) and 1.26 Earth-days (for Deimos) to circle the planet. You are given the task of coming up with a martian calendar for a new Mars colony. Would a solar or lunar calendar be better for tracking the seasons?arrow_forwardThe angular diameter and distance of the Moon are 31 minutes of arc and 384,400 km. Use the small angle equation to find the linear diameter of the Moonarrow_forwardDione, a moon of Saturn, has an orbital radius of 377,400 km, and an orbital period of about 2.737 Earth days. Find the orbital period of Rhea, another moon of Saturn, which has an orbital radius of 527,040 km. Find the period in Earth days. Round to the nearest hundredth. Don't worry about putting the unit, just put the answer.arrow_forward
- Suppose you were given a 3 in diameter ball to represent the Earth and a 1 in diameter ball to represent the Moon. (The actual ratio of Earth diameter to Moon diameter is 3.7 to 1.) The actual average Earth–Moon distance is about 384,000 kilometers, and Earth’s diameter is about 12,800 kilometers. How many “Earth diameters” is the distance from Earth to the Moon? Based on your answer to Question 2, what is the correct scaled distance of the Moon, using the 3-inch ball as Earth? The Sun’s actual diameter is about 1,400,000 kilometers. How many “Earth diameters” is this? Given your 3-inch Earth, how large (i.e what diameter) of a ball would you need to represent the Sun? Give your answer in feet. The average Earth–Sun distance is about 149,600,000 km. To represent this distance to scale, how far away would you have to place your 3-inch Earth from your Sun? Give your answer in feet. Could we use this scale to visualize the solar system instead of just the Earth and Moon? Why or Why…arrow_forwardThe mean radius of earth is 6,371.0 kilometers and the mean radius of earths moon is 1,737.5 kilometers. What is the approximate difference in the mean conferences, in kilometers, of earth and earths moon? Round your answer to the nearest tenth of a kilometer.arrow_forwardThe distance from the Sun to Earth is approximately 149,600,000 kilometers (km). The distance from the Sun to Mercury is approximately 57,910,000 km. The elongation angle is the angle formed between the line of sight from Earth to the Sun and the line of sight from Earth to Mercury. See the figure.Suppose that the elongation angle for Mercury is 15°. Use this information to find the possible distances between Earth and Mercury.arrow_forward
- As an aspiring science fiction author, you are writing about a space-faring race and their home planet, Krypton, which has one moon. This moon takes 1,702,948 seconds to complete an orbit around Krypton. If the distance from the center of the moon to the surface of Krypton is 462.5 x 106 m and the planet has a radius of 37.2 x 106 m, calculate the moon's centripetal acceleration. Your Answer: Answerarrow_forwardA moon's physical diameter is about 3200.0 km, and its orbital distance from its planet varies between 360,000 km and 413000.0 km. What is the moon's angular size in degrees at maximum distance from the planet?arrow_forwardThe Earth is about 12,000 km in diameter. It is therefore how many orders of magnitude wider than you are tall? (i.e., the Earth’s diameter is how many times larger than your height (give an order-of-magnitude estimate)?) (I am 5'2")arrow_forward
- Thinking about the Scale of the Solar System As we discussed, the radius of the Earth is approximately 6370 km. The Sun, on the other hand, is approximately 700,000 km in radius and located, on average, one astronomical unit (1 au=1.5x108 km) from the Earth. Imagine that you stand near Mansueto Library, at the corner of 57th and Ellis. You hold a standard desk globe, which has a diameter of 12 inches, and you want to build a model of the Sun, Earth, and their separation that keeps all sizes and lengths in proportion to one another. a) How big would the Sun be in this scale model? Give your answer in feet and meters. b) The nearest star to the Solar System outside of the Sun is Proxima Centauri, which is approximately 4.2 light years away (a light year is the distance light travels in one year, or approximately 9.5x1012 km). Given the scale model outlined above, how far would a model Proxima Centauri be placed from you? Give your answer in miles and km.arrow_forwardWhat would be the angular diameter of the Moon if to distance between the Moon and the Earth were twice bigger?arrow_forwardCalculate how many seconds there are in 1.0 Mars year (678 Earth days). Report your answer in scientific notation with the correct number of significant digits.arrow_forward
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