Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
1st Edition
ISBN: 9780078945830
Author: Charles William McLaughlin, Marilyn Thompson, Dinah Zike
Publisher: Glencoe Mcgraw-Hill
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Chapter 2, Problem 4STP
To determine

To Choose:The correct option.

Expert Solution & Answer
Check Mark

Answer to Problem 4STP

A correct answer is an option (B).

Explanation of Solution

Given:

From above graph, it is found that,

Distance travelled by the cyclist is d=5km .

Initial speed of the cyclist is 0km/h

Formula used:

The average speed is

  s=dt  ...... (1)

Here, d , t are the distance and time taken to travel.

Calculation:

The speed of the cyclist is the maximum at a distance between 2 km and 3 km after starting of the journey. The graph indicates the speed is maximum ( 30km/h ) at this point of distance 2.25 km on x-axis. So the options (a), (C), and (D) are wrong.

The cyclist has maximum of 30km/h in the graph given above. So, option (B) is correct answer.

Conclusion:

Hence,the fastest speed that the cyclist travelled is 30km/h .

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Speed Distance Time | Forces & Motion | Physics | FuseSchool; Author: FuseSchool - Global Education;https://www.youtube.com/watch?v=EGqpLug-sDk;License: Standard YouTube License, CC-BY