As stated in the chapter, carbon monoxide has a much higher affinity for hemoglobin than oxygen does. (a) Write the equilibrium constant expression (Kc) for the following process:
where HbO2 and HbCO are oxygenated hemoglobin and carboxyhemoglobin, respectively.
(b) The composition of a breath of air inhaled by a person smoking a cigarette is 1.9 × 10−6 mol/L CO and 8.6 × 10−3 mol/L O2. Calculate the ratio of [HbCO] to [HbO2], given that Kc is 212 at 37°C.
(a)
Interpretation:
The equilibrium constant expression
Concept introduction:
Equilibrium constant
Equilibrium constant
Consider the reaction where A reacts to give B.
On rearranging,
Where,
Answer to Problem 20.69QP
The equilibrium constant expression
Explanation of Solution
Given,
The balanced reaction between carbon monoxide and hemoglobin is given as
The equilibrium constant expression is the ratio of product of concentration of oxygen and
(b)
Interpretation:
From the equilibrium constant
Concept introduction:
Equilibrium constant
Equilibrium constant
Consider the reaction where A reacts to give B.
On rearranging,
Where,
Answer to Problem 20.69QP
The ratio of
Explanation of Solution
Given,
The balanced reaction between carbon monoxide and hemoglobin is given as
The equilibrium constant expression is given as,
The ratio of
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Chapter 20 Solutions
GENERAL CHEMISTRY LL
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- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning