The question asks one to write the equations corresponding to the oxidation of a primary alcohol and a secondary alcohol. Also one needs to specify the structure of each alcohol and the principal products of oxidation. Concept Introduction: Monohydric alcohols can be categorized into three types as primary, secondary and tertiary alcohols. AS shown above in primary alcohols carbon with the −OH group is bonded to only one carbon whereas in secondary alcohols, carbon with the −OH group is bonded to two other carbon atoms. In tertiary alcohols(not shown here), carbon with the −OH group is bonded to three other carbon atoms. In the alcohols the −OH bond is polarized placing partially negative charge on O atom while placing a partially positive charge on the alkyl carbon atom of the R-OH bond. Hence due to the inter molecular hydrogen bonds formed between alcohol molecules, their boiling points have higher values compared to the alkanes and ethers with comparable relative molecular masses.

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Answer 1

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 20, Problem 70QAP

Interpretation Introduction

Interpretation:

The question asks one to write the equations corresponding to the oxidation of a primary alcohol and a secondary alcohol. Also one needs to specify the structure of each alcohol and the principal products of oxidation.

Concept Introduction:

Monohydric alcohols can be categorized into three types as primary, secondary and tertiary alcohols.

AS shown above in primary alcohols carbon with the −OH group is bonded to only one carbon whereas in secondary alcohols, carbon with the −OH group is bonded to two other carbon atoms. In tertiary alcohols(not shown here), carbon with the −OH group is bonded to three other carbon atoms.

In the alcohols the −OH bond is polarized placing partially negative charge on O atom while placing a partially positive charge on the alkyl carbon atom of the R-OH bond. Hence due to the inter molecular hydrogen bonds formed between alcohol molecules, their boiling points have higher values compared to the alkanes and ethers with comparable relative molecular masses.

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Answer 2

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 20, Problem 70QAP

Interpretation Introduction

Interpretation:

The question asks one to write the equations corresponding to the oxidation of a primary alcohol and a secondary alcohol. Also one needs to specify the structure of each alcohol and the principal products of oxidation.

Concept Introduction:

Monohydric alcohols can be categorized into three types as primary, secondary and tertiary alcohols.

AS shown above in primary alcohols carbon with the −OH group is bonded to only one carbon whereas in secondary alcohols, carbon with the −OH group is bonded to two other carbon atoms. In tertiary alcohols(not shown here), carbon with the −OH group is bonded to three other carbon atoms.

In the alcohols the −OH bond is polarized placing partially negative charge on O atom while placing a partially positive charge on the alkyl carbon atom of the R-OH bond. Hence due to the inter molecular hydrogen bonds formed between alcohol molecules, their boiling points have higher values compared to the alkanes and ethers with comparable relative molecular masses.

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Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 20, Problem 70QAP

Interpretation Introduction

Interpretation:

The question asks one to write the equations corresponding to the oxidation of a primary alcohol and a secondary alcohol. Also one needs to specify the structure of each alcohol and the principal products of oxidation.

Concept Introduction:

Monohydric alcohols can be categorized into three types as primary, secondary and tertiary alcohols.

AS shown above in primary alcohols carbon with the −OH group is bonded to only one carbon whereas in secondary alcohols, carbon with the −OH group is bonded to two other carbon atoms. In tertiary alcohols(not shown here), carbon with the −OH group is bonded to three other carbon atoms.

In the alcohols the −OH bond is polarized placing partially negative charge on O atom while placing a partially positive charge on the alkyl carbon atom of the R-OH bond. Hence due to the inter molecular hydrogen bonds formed between alcohol molecules, their boiling points have higher values compared to the alkanes and ethers with comparable relative molecular masses.

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Check out a sample textbook solution

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Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 20, Problem 70QAP

Interpretation Introduction