GENERAL CHEMISTRY-SOLUTIONS MANUAL
11th Edition
ISBN: 9780132925044
Author: Petrucci
Publisher: PEARSON
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Question
Chapter 21, Problem 15E
Interpretation Introduction
Interpretation:
Whether the following process obeys the principal of conservation of charge or not should be determined. Explain.
In sea water, the starting material is
Concept introduction:
According to the principal of conservation of charges, the total charge of a given isolated system will never change. This means that the net electric charge which is equal to the subtraction of quantity of positive charge and the quantity of negative charge in this universe always remains conserved.
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Chapter 21 Solutions
GENERAL CHEMISTRY-SOLUTIONS MANUAL
Ch. 21 - Prob. 1ECh. 21 - Use information from the chapter to write chemical...Ch. 21 - Prob. 3ECh. 21 - Describe two methods for determining the identity...Ch. 21 - Arrange the following compounds in the expected...Ch. 21 - Prob. 6ECh. 21 - Prob. 7ECh. 21 - A lithium battery used in a cardiac pacemaker has...Ch. 21 - Prob. 9ECh. 21 - Prob. 10E
Ch. 21 - The standard Gibbs energies of formation, rG , for...Ch. 21 - Prob. 12ECh. 21 - Prob. 13ECh. 21 - Prob. 14ECh. 21 - Prob. 15ECh. 21 - Prob. 16ECh. 21 - Prob. 17ECh. 21 - Write chemical equations for the reactions you...Ch. 21 - Without performing detailed calculations, indicate...Ch. 21 - Prob. 20ECh. 21 - With respect to decomposition to MO(s) and SO2(g)...Ch. 21 - Prob. 22ECh. 21 - Prob. 23ECh. 21 - Prob. 24ECh. 21 - Prob. 25ECh. 21 - Prob. 26ECh. 21 - Prob. 27ECh. 21 - Prob. 28ECh. 21 - Prob. 29ECh. 21 - Prob. 30ECh. 21 - Prob. 31ECh. 21 - Prob. 32ECh. 21 - Prob. 33ECh. 21 - Prob. 34ECh. 21 - Prob. 35ECh. 21 - Prob. 36ECh. 21 - Prob. 37ECh. 21 - Prob. 38ECh. 21 - Prob. 39ECh. 21 - Prob. 40ECh. 21 - Prob. 41ECh. 21 - Prob. 42ECh. 21 - Prob. 43ECh. 21 - Prob. 44ECh. 21 - Methane and sulfur vapor react to form carbon...Ch. 21 - Prob. 46ECh. 21 - Prob. 47ECh. 21 - Prob. 48ECh. 21 - Write plausible chemical equations for the (a)...Ch. 21 - Prob. 50ECh. 21 - Prob. 51ECh. 21 - Aqueous tin(II) ion, Sn2+(aq) , is a good reducing...Ch. 21 - Would you expect the reaction of Sn(s) and Cl2(g)...Ch. 21 - Prob. 54ECh. 21 - Prob. 55IAECh. 21 - The following series of observations is made: (1)...Ch. 21 - Prob. 57IAECh. 21 - Prob. 58IAECh. 21 - Prob. 59IAECh. 21 - Prob. 60IAECh. 21 - Lithium superoxide, LiO2(s) , has never been...Ch. 21 - Prob. 62IAECh. 21 - Prob. 63IAECh. 21 - Prob. 64IAECh. 21 - Use data from Appendix D (Table D-2) to calculate...Ch. 21 - Prob. 66IAECh. 21 - A particular water sample contains 56.9 ppm SO42-...Ch. 21 - An aluminum production cell of the type pictured...Ch. 21 - Prob. 69IAECh. 21 - Prob. 70IAECh. 21 - Prob. 71IAECh. 21 - Prob. 72IAECh. 21 - Prob. 73IAECh. 21 - Prob. 74IAECh. 21 - Prob. 75IAECh. 21 - Would you expect the lattice energy of MgS(s) to...Ch. 21 - Prob. 77IAECh. 21 - Prob. 78FPCh. 21 - Prob. 79FPCh. 21 - Prob. 80SAECh. 21 - Briefly describe each of the following ideas,...Ch. 21 - Explain the important distinction between each...Ch. 21 - Prob. 83SAECh. 21 - Prob. 84SAECh. 21 - Predict the products of the following reactions:...Ch. 21 - A chemist knows that aluminum is more reactive...Ch. 21 - Listed are several pairs of substances. For some...Ch. 21 - Prob. 88SAECh. 21 - Prob. 89SAECh. 21 - Prob. 90SAECh. 21 - Prob. 91SAECh. 21 - Prob. 92SAECh. 21 - Prob. 93SAECh. 21 - Prob. 94SAECh. 21 - Prob. 95SAE
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- The amount of sodium hypochlorite in a bleach solution can be determined by using a given volume of bleach to oxidize excess iodide ion to iodine; ClO- is reduced to Cl-. The amount of iodine produced by the redox reaction is determined by titration with sodium thiosulfate, Na2S2O3; I2 is reduced to I-. The sodium thiosulfate is oxidized to sodium tetrathionate, Na2S4O6. In this analysis, potassium iodide was added in excess to 5.00 mL of bleach (d=1.00g/cm3) . If 25.00 mL of 0.0700 M Na2S2O3 was required to reduce all the iodine produced by the bleach back to iodide, what is the mass percent of NaClO in the bleach?arrow_forwardThe amount of sodium hypochlorite in a bleach solution can be determined by using a given volume of bleach to oxidize excess iodide ion to iodine, because the reaction goes to completion. The amount of iodine produced is then determined by titration with sodium thiosulfate, Na2S2O3, which is oxidized to sodium tetrathionate, Na2S4O6. Potassium iodide was added in excess to 5.00 mL of bleach (density = 1.00 g/mL). This solution, containing the iodine released in the reaction, was titrated with 0.100 M Na2S2O3. If 34.6 mL of sodium thiosulfate was required to reach the endpoint (detected by disappearance of the blue color of the starch iodine complex), what was the mass percentage of NaClO in the bleach?arrow_forwardThree reactions very important to the semiconductor industry are The reduction of silicon dioxide to crude silicon, SiO2(s) + 2 C(s) → Si(s) + 2 CO(g) ΔrH° = 689.9 kJ/mol The formation of silicon tetrachloride from crude silicon, Si(s) + 2 Cl2(g) → SiCl4(g) ΔrH° = −657.01 kJ/mol The reduction of silicon tetrachloride to pure silicon with magnesium, SiCl4(g) + 2 Mg(s) → 2 MgCl2(s) + Si(s) ΔrH° = −625.6 kJ/mol Calculate the overall enthalpy change when 1.00 mol sand, SiO2, changes into very pure silicon by this series of reactions.arrow_forward
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