EBK STARTING OUT W/JAVA:...DATA...
EBK STARTING OUT W/JAVA:...DATA...
4th Edition
ISBN: 9780134757179
Author: GADDIS
Publisher: PEARSON CO
Expert Solution & Answer
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Chapter 21, Problem 1FTE

Explanation of Solution

Given program code:

//Return the number of nodes in a binary tree

int Nodecount (Node tree) //Line 1

{ //Line 2

    //Declare a variable to get the number of nodes

    int count = 0; //Line 3

    //Check if tree is not equal to null

    if (tree != null) //Line 4

    { //Line 5

        //Increment the value of count

        count++; //Line 6

//Call the function recursively by passing the left sub tree

        NodeCount(tree.left); //Line 7

//Call the function recursively by passing the right sub tree

        NodeCount(tree.right); //Line 8

    } //Line 9

    //Return the value of count

    return count;//Line 10

}//Line 11

The above program code snippet is used to find the number of nodes present in the binary tree.

Error in the program code:

The statements inside the “if” condition does not use the returned values from the recursive calls. The lines from “Line 6” to “Line 10” should be changed and the modified snippet is given below...

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2. Write the code for preorder traversal of a binary tree. struct node{ int data; struct node *left, *right; } void preorder(node *x) { }
What does this part of code do? void addRecord(Node *& head, Node *& tail, string name, double balance){    Node *newNode = new Node;    newNode->name = name;    newNode->balance = balance;    newNode->next = NULL;    newNode->prev = NULL;    // If list is empty, make newNode the first node    if(head == NULL){        head = newNode;        tail = newNode;    }    else{        Node *temp = head;        // Loop through list until temp->next is NULL        while(temp->next != NULL){            temp = temp->next;        }        temp->next = newNode;        newNode->prev = temp;        tail = newNode;    }} /*
Assume the tree node structure is following........ struct node { int data; struct node* left; struct node* right; }; struct node *root = null; and there is a created new node function, called newnode(int new_data). Please filled the Blank of Insertion function. void insert(struct node *root, int key) { struct node *current; queue q; q.enque(root); while(!q.empty() } current = q.front(); q.deque(); if(current->left == NULL) { break; } else } q.enque( if(current->right == NULL) { break; else q.enque(_ = newnode(key); = newnode(key); _-));
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