OWLv2 with Student Solutions Manual eBook for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 4 terms (24 months)
11th Edition
ISBN: 9781305864900
Author: Darrell Ebbing; Steven D. Gammon
Publisher: Cengage Learning US
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Question
Chapter 21, Problem 21.108QP
(a)
Interpretation Introduction
Interpretation:
The result of addition of hydroxide ion to aluminum ion has to be explained.
Concept introduction:
Complex compound or ion which comprises more than two different chemical components. Formation of complex compounds converts precipitate into solution.
(b)
Interpretation Introduction
Interpretation:
The complete and balanced equation of the given reaction has to be written.
Concept introduction:
Balanced Chemical equation:
A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.
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A solution of potassium dichromate is made basic with sodium hydroxide;the color changes from red to yellow. Addition of silver nitrate to the yellow solution gives a precipitate. This precipitate dissolves in concentrated ammonia but re-forms when nitric acid is added. Write balanced net ionic equations for all the reactions in this sequence.
Write the balanced equation for each reaction. Phases are optional.
The carbonate ion (CO) acts as a Brønsted base with water.
equation:
The carbon-containing product from the first reaction acts as a Brønsted base with water.
equation:
The carbon-containing product from the second reaction decomposes into carbon dioxide gas and water.
equation:
Consider the products of the reactions. When the carbonate ion reacts with water, is the resulting solution acidic or basic?
basic
acidic
For each of the following pairs of substances
• Classify each of the substances.
• Compare their approximate pH levels.
• Compare their ability to conduct electricity.
• Compare their relative hydronium or hydroxide concentration.
Comparison of 1.0 mol/L LIOH(aq) and 1.0 mol/L HOCI(aq)
• LIOH(aq) is classified as a
• HOCI(aq) is classified as a
• HOCI(aq) has a
+ pH than LIOH(aq) has.
. нос(ag) is a
+ electrical conductor than LIOH(aq) is.
LIOH(aq) has a
: [OH (aq)] than HOCI(aq) has.
Comparison of 1.0 mol/L HCN(aq) and 1.0 mol/L KF(aq)
• KF(aq) is classified as a
• HCN(aq) is classified as a
• HCN(aq) has a
: pH than KF(aq) has.
• HCN(aq) is a
+ electrical conductor than KF(ag) is.
• HCN(aq) has a
+ [H30+(aq)] than KF(aq) has.
Chapter 21 Solutions
OWLv2 with Student Solutions Manual eBook for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 4 terms (24 months)
Ch. 21.9 - Considering the fact that N2 makes up about 80% of...Ch. 21.10 - Prob. 21.2CCCh. 21 - Prob. 21.1QPCh. 21 - Prob. 21.2QPCh. 21 - Prob. 21.3QPCh. 21 - Prob. 21.4QPCh. 21 - Prob. 21.5QPCh. 21 - Prob. 21.6QPCh. 21 - Prob. 21.7QPCh. 21 - Prob. 21.8QP
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