Concept explainers
Review. As a sound wave passes through a gas, the compressions are either so rapid or so far apart that thermal
where M is the molar mass. The speed of sound in a gas is given by Equation 16.35; use that equation and the definition of the bulk modulus from Section 12.4. (b) Compute the theoretical speed of sound in air at 20.0°C and state how it compares with the value in Table 16.1. Take M = 28.9 g/mol. (c) Show that the speed of sound in an ideal gas is
where m0 is the mass of one molecule. (d) Slate how the result in part (c) compares with the most probable, average, and rms molecular speeds.
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Chapter 21 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
- 35. ssm The speed of a sound in a container of hydrogen at 201 K is 1220 m/s. What would be the speed of sound if the temperature were raised to 405 K? Assume that hydrogen behaves like an ideal gas.arrow_forwardB1arrow_forwardThe accepted value for the speed of sound in dry air is 331.50 m/s at 0 °C. This speed increases by 0.607 m/s for each additional °C. Compute the accepted value for the speed of sound in air at a room temperature of 27 °C, also known as 300 K because T = 273.15 + t ( Here t is in degree Celsius).arrow_forward
- The speed of sound in an ideal gas (not air) is 750 m/s at -50°C. What is the speed of sound in the same gas at T = 55°C? The absolute zero temperature is -273.15°C. The speed of sound, cs(T = 55°C) = Unitsarrow_forwardA sound wave has a frequency of 632 Hz in air and a wavelength of 0.51 m. What is the temperature of the air? Assume the velocity of sound at 0°C is 331 m/s. Answer in units of °C.arrow_forwardYou have two air columns that are each 2.330 m long. One column is open at both ends and the other is closed at one end. You wish to determine the frequencies you can produce in the audible range (20 Hz–20,000 Hz) on a day when the temperature of the air is at 26.00°C. (Give your answers to at least four significant figures. Assume that the speed of sound at 0° C is exactly 331 m/s.) (a) in the column that is open at both ends: lowest frequency, second lowest frequency and highest frequency (b) in the column that is closed at one end: lowest frequency, second lowest frequency and highest frequencyarrow_forward
- At what temperature is the speed of sound in helium (ideal gas, = 1.67, atomic mass = 4.003 u) the same as its speed in oxygen gas at 5.40 oC? The speed of sound in oxygen at 5.40°C is 318 m/s.arrow_forwardA flute is designed so that it plays a frequency of 268.2 Hz, when all the holes are covered and the temperature is 18.2°C. (a) What is the speed of sound in the flute? A flute is designed so that it plays a frequency of 268.2 Hz, when all the holes are covered and the temperature is 18.2°C. (b) What is the wavelength of the first harmonic? Consider the flute to be a pipe open at both ends A flute is designed so that it plays a frequency of 268.2 Hz, when all the holes are covered and the temperature is 18.2°C. (c)Consider the flute to be a pipe open at both ends and find its length, assuming this frequency is the fundamental frequency A flute is designed so that it plays a frequency of 268.2 Hz, when all the holes are covered and the temperature is 18.2°C. A second player, nearby in a colder room, also attempts to play middle C on an identical flute. A beat frequency of 3.00 beats/s is heard. (e) What is the speed of sound in the second room? A flute is designed so that it plays a…arrow_forward*44. GO A monatomic ideal gas (y = 1.67) is contained within a box whose volume is 2.5 m². The pressure of the gas is 3.5 × 10° Pa. The total mass of the gas is 2.3 kg. Find the speed of sound in the gas.arrow_forward
- A long tube contains air pressure of 1atm1atm and a temperature of 59oC. The tube is open at one end and closed at the other by a movable piston. A tuning fork near the open end is vibrating with a frequency of 500Hz. Resonance is produced when the piston is at distances 16cm,49.2cm and 82.4cm from open end. Molar mass of air is 28.8g/mol. Determine the speed of sound in air at 590C.arrow_forwarda) Use the following equation 1/2 Bm 8(v.)dv, = () exp(-Bm? )dv. 2n to show that in one dimension the root mean square velocity is given by KT\ '/2 Vrms = (Verms) m b) Show that the first equation of this exercise can be described by 8(vx)dvx = (27)¯1/² (vxrms)¯' exp| dvxarrow_forwardAt 0 oC, the speed of sound in air is 330 m/s. How much faster is sound, at an air temperature of 22.3 oCarrow_forward
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