ETEXT+MASTERINGCHEMISTRY STANDALONE AC
7th Edition
ISBN: 9781269736947
Author: Bruice
Publisher: PEARSON
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Chapter 21, Problem 42P
Interpretation Introduction
Interpretation:
The hexose obtained after three successive Killiani-Fisher synthesis of (+)-glyceraldehyde is to be predicted on the basis of given information.
Concept Introduction:
In Killiani-Fisher synthesis, hydrogen cyanide attacks the carbonyl group. The carbonyl carbon is converted to an asymmetric center. The
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d-Xylose and d-lyxose are formed when d-threose undergoes a Kiliani–Fischer synthesis. d-Xylose is oxidized to an optically inactive aldaric acid,whereas d-lyxose forms an optically active aldaric acid. What are the structures of d-xylose and d-lyxose?
Which D-aldopentose is oxidized to an optically active aldaric acid and undergoes the Wohl degradation to yield a Daldotetrose that is oxidized to an optically active aldaric acid?
An unknown β-d-aldohexose has only one axial substituent. A Wohl degradation forms a compound which, when treated with sodium borohydride, forms an optically active alditol. This information allows you to arrive at two possible structures for the β-d-aldohexose. What experiment can you carry out to distinguish between the two possibilities?
Chapter 21 Solutions
ETEXT+MASTERINGCHEMISTRY STANDALONE AC
Ch. 21.1 - Prob. 1PCh. 21.2 - Prob. 2PCh. 21.2 - Prob. 3PCh. 21.3 - Prob. 4PCh. 21.3 - Prob. 5PCh. 21.3 - Prob. 6PCh. 21.4 - Prob. 7PCh. 21.4 - Prob. 8PCh. 21.5 - Prob. 9PCh. 21.5 - Prob. 10P
Ch. 21.5 - Prob. 11PCh. 21.6 - Prob. 12PCh. 21.6 - Prob. 13PCh. 21.6 - Prob. 14PCh. 21.7 - Prob. 15PCh. 21.8 - Prob. 16PCh. 21.9 - Prob. 18PCh. 21.10 - Prob. 20PCh. 21.10 - Prob. 21PCh. 21.10 - Prob. 22PCh. 21.11 - Prob. 24PCh. 21.11 - Prob. 25PCh. 21.15 - Prob. 27PCh. 21.16 - Prob. 28PCh. 21.17 - Prob. 29PCh. 21.18 - Refer to Figure 20.5 to answer the following...Ch. 21 - Prob. 31PCh. 21 - Prob. 32PCh. 21 - Prob. 33PCh. 21 - Prob. 34PCh. 21 - Prob. 35PCh. 21 - Prob. 36PCh. 21 - Prob. 37PCh. 21 - Prob. 38PCh. 21 - Prob. 39PCh. 21 - Prob. 40PCh. 21 - Prob. 41PCh. 21 - Prob. 42PCh. 21 - Prob. 43PCh. 21 - Prob. 44PCh. 21 - The 1H NMR spectrum of D-glucose in D2O exhibits...Ch. 21 - Prob. 46PCh. 21 - Prob. 47PCh. 21 - Prob. 48PCh. 21 - Prob. 49PCh. 21 - Prob. 50PCh. 21 - Prob. 51PCh. 21 - Prob. 52PCh. 21 - Prob. 53PCh. 21 - Prob. 54PCh. 21 - Prob. 55PCh. 21 - A hexose is obtained when the residue of a shrub...Ch. 21 - Prob. 57PCh. 21 - Prob. 58PCh. 21 - Prob. 59PCh. 21 - Prob. 60PCh. 21 - Prob. 61PCh. 21 - Prob. 62PCh. 21 - Prob. 63PCh. 21 - Prob. 64PCh. 21 - Prob. 65PCh. 21 - Prob. 66P
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- An optically active D-aldopentose (A) produced an optically inactive alditol (B) upon treatment with H2/Pt. When the aldopentose (A) was subjected to a Ruff degradation, D-aldotetrose (C) was generated. The aldotetrose (C) gave an optically active aldaric acid (D) upon oxidation with HNO3. D-aldopentose (A) can be prepared from D-threose by a Killani Fischer synthesis. Propose structure of A through D.arrow_forwardRuff degradation of d-arabinose gives d-erythrose. The Kiliani–Fischer synthesis converts d-erythrose to a mixture of d-arabinose and d-ribose. Draw out these reactions, andgive the structure of d-ribosearrow_forwardAldohexoses A and B both undergo Ruff degradation to give aldopentose C. On treatment with warm nitric acid, aldopentose C gives an optically active aldaric acid. B alsoreacts with warm nitric acid to give an optically active aldaric acid, but A reacts to givean optically inactive aldaric acid. Aldopentose C is degraded to aldotetrose D, whichgives optically active tartaric acid when it is treated with nitric acid. Aldotetrose D isdegraded to (+)@glyceraldehyde. Deduce the structures of sugars A, B, C, and D, and useFigure 23-3 to determine the correct names of these sugars.arrow_forward
- d-Altrose is an aldohexose. Ruff degradation of d-altrose gives the same aldopentose asdoes degradation of d-allose, the C3 epimer of glucose. Give the structure of d-altrosearrow_forwardIllustrate the treatment of methyl α-D-glucopyranoside with aqueous acid forms a mixture of α- and β-D-glucose and methanol ?arrow_forward(a) Which of the d-aldopentoses will give optically active aldaric acids on oxidation with HNO3 ?(b) Which of the d-aldotetroses will give optically active aldaric acids on oxidation with HNO3 ?(c) Sugar X is known to be a d-aldohexose. On oxidation with HNO3, X gives an optically inactive aldaric acid. WhenX is degraded to an aldopentose, oxidation of the aldopentose gives an optically active aldaric acid. Determine thestructure of X.(d) Even though sugar X gives an optically inactive aldaric acid, the pentose formed by degradation gives an opticallyactive aldaric acid. Does this finding contradict the principle that optically inactive reagents cannot form opticallyactive products?(e) Show what product results if the aldopentose formed from degradation of X is further degraded to an aldotetrose.Does HNO3 oxidize this aldotetrose to an optically active aldaric acid?arrow_forward
- Draw the product that is expected when the β-pyranose form of compound A is treated with excess ethyl iodide in the presence of silver oxide. The following information can be used to determine the identity of compound A: The molecular formula of compound A is C6H12O6. Compound A is reducing sugar. When compound A is subjected to a Wohl degradation two times sequentially, Derythrose is obtained. Compound A is epimeric with D-glucose at C3. The configuration at C2 is R.EXPLAIN IN DETAIL.arrow_forwardAn oligosaccharide isolated from an organism is found tocontain two glucose residues and one galactose residue.Exhaustive methylation followed by hydrolysis producedtwo glucoses with methoxy groups at positions 2, 3,and 6 and galactose with methoxy groups at positions2, 3, 4, and 6. What is the structure of the originaloligosaccharide?arrow_forwardShow that Ruff degradation of d-mannose gives the same aldopentose (d-arabinose) asdoes d-glucosearrow_forward
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