Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
4th Edition
ISBN: 9780134787961
Author: Tony Gaddis, Godfrey Muganda
Publisher: PEARSON
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Chapter 21, Problem 4AW

Explanation of Solution

Binary search tree:

  • Binary search tree is a tree in which the nodes are sorted in the semantic order and it has the shape of binary tree.
  • Nodes in the binary search tree can have zero, one, or two children.
  • In a binary search tree, any node value is greater than the left sub tree and lesser than the right sub tree.
    • Node without children is called a leaf or end node.
    • A node that does not have a superior node is called a root node.
    • Root node is the starting node.
  • The binary search will be performed until finding a search node or reaching the end of the tree.

Algorithm to count the number of leaf in a binary tree:

Step 1: Define a function named “leafCount” with the parameter “btree”.

Step 2: Check if “btree” is equal to null. If it is true, then return 0.

Step 3: Check if “btree.left” is equal to null and “btree.right” is equal to null. If this condition is true, then return 1.

Step 4: If both the condition fails, then return the summation of count of left tree and right tree by calling the function “leafCount ()” recursively...

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Students have asked these similar questions
Write a method called removeLeaves thatremoves the leaves from a tree.
Write a method isBST() that takes a Node as argument and returns true if the argument node is the root of a binary search tree, false otherwise.Hint : This task is also more difficult than it might seem, because the order in which youcall the methods in the previous three exercises is important.
Write a method hasNoDuplicates() that takes a Node as argument and returns true if there are no equal keys in the binary tree rooted at the argument node, false otherwise. Assume that the test of the previous exercise has passed.
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