Concept explainers
(a)
The magnitude and the direction of the force exerted.
(a)
Explanation of Solution
Given:
Four point charges placed at corners of a square whose edge length is L.
Formula used:
Write the expression for the net force acting on
Here,
Write the expression for the
Here,
Write the expression for the
Here,
The magnitude of charge
Here,
Substitute
Substitute
Substitute
Calculation:
Substitute
Conclusion:
Thus, the magnitude and the direction of the force is
(b)
The magnitude of the electric field.
(b)
Explanation of Solution
Formula used:
Write the expression for the electric field at
Here,
Write the expression for the electric field due to charge
Here,
Write the expression for the electric field due to charge
Here,
Write the expression for the electric field due to charge
Here,
Write the expression for the electric field due to charge
Here,
Substitute
Substitute
Substitute
Substitute
Calculation:
Substitute
Conclusion:
Thus, the magnitude and the direction of the electric field is
Want to see more full solutions like this?
Chapter 21 Solutions
PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
- A proton is fired from very far away directly at a fixed particle with charge q = 1.28 1018 C. If the initial speed of the proton is 2.4 105 m/s, what is its distance of closest approach to the fixed particle? The mass of a proton is 1.67 1027 kg.arrow_forwardthree point charges in 1Darrow_forwardCommon static electricity involves charges ranging from nanocoulombs to microcoulombs. (a) How many electrons are needed to form a charge of –2.00 nC (b) How many electrons must be removed from a neutral object to leave anet charge of 0.500 μC ?arrow_forward
- Dipole consisting of two equal but opposite point charges separated by a distance "2L". The magnitude either dipole charge is , "qd". A vector quantity called the Electric Dipole Moment Vector ,p ,is defined to have a magnitude p = (qd)(d) (d= separation distance of the dipole charges) and a unit vector direction pointing from negative to positve charge Find the dipole moment vector “p”arrow_forwardTwo positive point charges of modulo q are separated from a negative charge of modulo 2q by a distance d and the three are arranged along a straight line. b) Find the behavior of the field obtained for distances much greater than the distance d separating the positive and negative charges.arrow_forwardThe force experienced by a unit charge when placed at a distance of 0.10 m from the middle of an electric dipole on its axial line is 0.025 N and when it is place at a distance of 0.2 m, the force is reduced to 0.002 N. Calculate the dipole length.arrow_forward
- Common transparent adhesive tape becomes charged when pulled from a dispenser. If one piece is placed above another, the repulsive force can be great enough to support the top piece’s weight. Assuming equal point charges as an approximation, calculate the magnitude of each charge, in coulombs, if the electrostatic force is great enough to support the weight of a 1.05 mg piece of tape held 0.85 cm above another.arrow_forwardр Σπερχε can A water molecule (H2O) has a dipole moment of 6.17 x 10-30 C. m. A water molecule located at the origin whose dipole moment P points in the +x-direction. A chlorine ion (CI), of charge -1.60 × 10-19 C, is located at x = 2.99 × 10-9 m. Find the size and direction of the electric force that the water molecule exerts on the chlorine ion. Assume that x is much larger than the separation d between the charges in the dipole, so that the approximate expression for the electric field along the dipole axis E = be used, where p is the dipole moment, and x is the distance between ions. magnitude N Is this force attractive or repulsive? attractive O repulsivearrow_forwardA uniformly charged disk of radius 35.0 cm carries acharge density of 7.90 103 C/m2. Calculate theelectric field on the axis of the disk at (a) 5.00 cm, (b) 10.0 cm, (c) 50.0 cm, and (d) 200 cm from the center of the disk.arrow_forward
- Plz solve this advance physics problem asaparrow_forwardA −5nC point charge is on the x-axis at x = 1.2m A second point charge Q is onthe x-axis at -0.600m. What must be the sign and magnitude of Q for the resultantelectric field at the origin to be (a) 45.0N/C in the +x-direction, (b) 45.0N/C in the -x-direction?arrow_forward+6e -4e Fig 21-12(1) Two conducting spheres are brought into contact. When they are touching each other, what is the charge in Coulombs on the left- most sphere? i Carrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning