Rising Median AGE Increased longevity and the aging of the baby boom generation—those born between 1946 and 1965—are the primary reasons for a rising median age. The median age (in years) of the U.S. population from 1900 through 2011 is approximated by the function
where t is measured in decades, with t = 0 corresponding to the beginning of 1900.
What was the median age of the U.S. population at the beginning of 1900? At the beginning of 1950? At the beginning of 2000?
b. Sketch the graph of f.
Source: U.S. Census Bureau.
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Chapter 2 Solutions
Applied Calculus for the Managerial, Life, and Social Sciences: A Brief Approach
- Sales Growth In this exercise, we develop a model for the growth rate G, in thousands of dollars per year, in sales of the product as a function of the sales level s, in thousands of dollars. The model assumes that there is a limit to the total amount of sales that can be attained. In this situation, we use the term unattained sales for difference this limit and the current sales level. For example, if we expect sales grow to 3 thousand dollars in the long run, then 3-s is the unattained sales. The model states that the growth rate G is proportional to the product of the sales level s, and the unattained sales. Assume that the constant of proportionality is 0.3 and that the sales grow to 2 thousand dollars in the long run. a.Find the formula for unattained sales. b.Write an equation that shows the proportionality relation for G. c.On the basis of the equation from the part b, make a graph of G as a function of s. d.At what sales level is the growth rate as large as possible? e.What is the largest possible growth rate?arrow_forwardDecay of Litter Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be the amount of litter present, in grams per square meter, as a function of time t in years. If the litter falls at a constant rate of L grams per square meter per year, and if it decays at a constant proportional rate of k per year, then the limiting value of A is R=L/k. For this exercise and the next, we suppose that at time t=0, the forest floor is clear of litter. a. If D is the difference between the limiting value and A, so that D=RA, then D is an exponential function of time. Find the initial value of D in terms of R. b. The yearly decay factor for D is ek. Find a formula for D in term of R and k. Reminder:(ab)c=abc. c. Explain why A=RRekt.arrow_forwardPopulation Growth and Decline The graph shows the population P in a small industrial city from 1950 to 2000. Thevariable x represents the number of year since 1950. (a) Determine the intervals on which the function P isincreasing and on which it is decreasing. (b) What as the maximum population, and in what yearwas it attained? (c) Find the net change in the population P from 1970 to 1990.arrow_forward
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