For Exercises 1-5, choose the correct letter.
Josephine measured the room to be
A.
B.
C.
D.
To find : the maximum possible area of the room. .
Answer to Problem 3STP
D.
Explanation of Solution
Given information: Joseph measured the room to be 125 ft wide and 225 ft long.
Calculation:
The degree of accuracy is half a unit of measure.
The measurement was made to the nearest ft , so the greatest possible error is half of 1 ft, that is 0.5 ft.
Therefore, maximum measurement of the width and length of the room are (125+0.5) ft and (225+0.5) ft, that is 125.5 ft by 225.5 ft. respectively.
Therefore, maximum possible area of the room is
Thus, maximum possible area of the room is
Chapter 2 Solutions
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