Chapter 2.2, Problem 14PSB

To determine

To calculate: $\angle AOC$ and $\angle AOB$

Answer to Problem 14PSB

  ${45}^{\circ }$ And ${45}^{\circ }$

Explanation of Solution

Given information:

  

Calculation: AS given in the graph ,OC bisects $\angle AOB$ . Since X and y axis are perpendicular to each other, hence $\therefore \angle AOC+\angle COB={90}^{\circ }$

  $\therefore \angle AOC+\angle COB={90}^{\circ }$

But $\therefore \angle AOC=\angle COB.$

  $\therefore \angle AOC={45}^{\circ }$ And $\angle COB={45}^{\circ }$