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The electric field
Figure P22.37
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- 33. What is the magnitude of the electric flux passing a square sheet of paper with an area of 25mm2 and an electric field of 2000 N/C that creates an angle of 63.5° from the normal line? From the problem, which of the following is the correct way of writing the given? Group of answer choices E = 2000 N/C; r = 25mm; θ = 63.5° E = 2000 N/C ; A = 25mm2; φ = 63.5° E = 2000 N/C ; r = 25mm2; φ = 63.5° E = 2000 N/C; A = 25mm2 θ = 63.5°arrow_forwardAn electric field of intensity 3.40 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the following conditions are true. (a) The plane is parallel to the yz-plane.____________N · m2/C(b) The plane is parallel to the xy-plane._____________N · m2/C(c) The plane contains the y-axis, and its normal makes an angle of 35.0° with the x-axis.______________N · m2/Carrow_forwardA figure shows a closed cylinder with a cross-sectional area A = 3.60 m2. The upper and lower circular surfaces of a vertically-oriented cylinder are labeled A. Electric field vector Epoints vertically upward, going up through the lower surface, up through the cylinder, and finally pointing up through the upper surface.The constant electric field has magnitude 2.85 ✕ 103 N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines pass through the curved surface. Calculate the electric flux (in (N · m2)/C) through the cylinder's top and bottom surfaces. (a)top surface __________ N · m2 C (b)bottom surface _______ NM^2/C (c)Determine the amount of charge (in C) inside the cylinder. _______Carrow_forward
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