Consider the reaction
Given that the ΔG° for the reaction at 298 K is 173.4 kJ/mol, calculate (a) the standard free energy of formation of NO, (b) KP for the reaction, (c) Kc for the reaction.
(a)
Interpretation:
For the formation of
Concept introduction:
Gibb’s free energy: The relationship between temperature and thermodynamic properties like enthalpy and entropy is given by Gibb’s free energy. Based on the value of Gibb’s free energy the feasibility of reactions can be explained.
To calculate: Gibb’s free energy change for the formation of
Answer to Problem 22.51QP
Gibb’s free energy change for the given reaction
Explanation of Solution
Formation reaction of
Given that, Gibb’s free energy change of the reaction at 298 K
General equation for calculation of Gibb’s free energy change of the given reaction
Apply the formula for the given reaction
Substances in elemental form (here oxygen and nitrogen molecule) have Gibb’s free energy of formation value is zero.
Gibb’s free energy change for the formation of
Gibb’s free energy change for the formation of
(b)
Interpretation:
For the formation of
Concept introduction:
Gibb’s free energy: The relationship between temperature and thermodynamic properties like enthalpy and entropy is given by Gibb’s free energy. Based on the value of Gibb’s free energy the feasibility of reactions can be explained.
To calculate: The
Answer to Problem 22.51QP
For the given reaction, value of
Explanation of Solution
The relationship between
Substitute the values of
By the use of relationship between
(c)
Interpretation:
For the formation of
Concept introduction:
Gibb’s free energy: The relationship between temperature and thermodynamic properties like enthalpy and entropy is given by Gibb’s free energy. Based on the value of Gibb’s free energy the feasibility of reactions can be explained.
To calculate: The
Answer to Problem 22.51QP
For the given reaction value of
Explanation of Solution
The relationship between
Here no change in number of moles, therefore,
By the use of relationship between
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Chapter 22 Solutions
Connect for Chemistry
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